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3 years ago

Calculate the kinetic energy in joules of an automobile weighing 4345 lb and traveling at 75 mph. (1 mile

Physics

2 answers:

kompoz [17]3 years ago

7 0

KE=1/2mv2
=1/2x1970.859x120701x120701
= 1.4356458e+13

adell [148]3 years ago

6 0

Answer:

1.11×10⁶ J

Explanation:

75 mi/hr × (1609.34 m / mi) × (1 hr / 3600 s) = 33.5 m/s

4345 lbf × (1 lbm / lbf) × (1 kg / 2.2 lbm) = 1975 kg

KE = 1/2 mv²

KE = 1/2 (1975 kg) (33.5 m/s)²

KE = 1.11×10⁶ J

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A string under a tension of 68 N is used to whirl a rock in a horizontal circle of radius 3.7 m at a speed of 16.53 m/s. The str

alekssr [168]

Answer:

$F = 5253.7 N$

Explanation:

As we know that tension force in the string will be equal to the centripetal force on the string

so we will have

$T = \frac{mv^2}{L}$

now we have

$68 = \frac{m(16.53^2)}{3.7}$

now we have

$68 = 73.8 m$

$m = 0.92 kg$

now when string length is 0.896 m and its speed is 71.5 m/s then we will have

$F = \frac{mv^2}{r}$

$F = \frac{0.92(71.5^2)}{0.896}$

$F = 5253.7 N$

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3 years ago

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The weight of a standard object defined as having a mass of exactly 2.9 kg is measured to be 28.449 n. in the same laboratory, a

PtichkaEL [24]

Mass of the object m = 2.9 kg
Force F1 = 28.449 N
F1 = m1 x a => a = F / m => 28.449 / 2.9 => a = 9.81, which is gravitational acceleration.
In the same lab, a = g = 9.81, second object F2 = 48.7N = m2 x a
m2 = F2 / a => 48.7 / 9.81 => m2 = 4.96 kg
Mass of the second object m2 = 4.96 kg

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3 years ago

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3 years ago

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Elena-2011 [213]

Answer:

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