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Iteru [2.4K]
3 years ago
5

Symbol of science hhshsjsiwtwwisjzhJava​

Physics
1 answer:
Rudik [331]3 years ago
6 0

Answer:

is this a company name.? java is a computer software right..

You might be interested in
9. How much work is done when a 15kg box is lifted to a height of 2 meters?
torisob [31]

Answer: W = 294 J

Explanation: Solution:

Work is expressed as the product of force and the distance of the object.

W = Fd        where F = mg

W= Fd

   = mg d

   = 15 kg ( 9.8 m/s²) ( 2m )

   = 294 J

5 0
4 years ago
A particular automotive wheel has an angular moment of inertia of 12 kg*m^2, and is decelerated from 135 rpm to 0 rpm in 8 secon
lozanna [386]

Answer:

(A) Torque required is 21.205 N-m

(b) Wok done will be equal to 1199.1286 j

Explanation:

We have given moment of inertia I=12kgm^2

Wheel deaccelerate from 135 rpm to 0 rpm

135 rpm = 135\times \frac{2\pi }{60}=14.1371rad/sec

Time t = 8 sec

So angular speed \omega _i=135rpm and \omega _f=0rpm

Angular acceleration is given by \alpha =\frac{\omega _f-\omega _i}{t}=\frac{0-14.1371}{8}=--1.7671rad/sec^2

Torque is given by torque \tau =I\alpha

=12\times 1.7671=21.205N-m

Work done to accelerate the vehicle is

\Delta w=K_I-K_F

\Delta W=\frac{1}{2}\times 12\times 14.137^2-\frac{1}{2}\times 12\times0^2=1199.1286J

8 0
4 years ago
Please I need help........
LenKa [72]

Answer:

7.46 J/kg/K

Explanation:

The heat absorbed or lost is:

q = mCΔT

where m is the mass, C is the heat capacity, and ΔT is the change in temperature.

Given q = 15.0 J, m = 0.201 kg, and ΔT = 10.0 °C:

15.0 J = (0.201 kg) C (10.0 °C)

C = 7.46 J/kg/°C

Which is the same as 7.46 J/kg/K.

7 0
3 years ago
Read 2 more answers
The motor of a ski boat generates an average power of 2.74 × 10^4 W when the boat is moving at a constant speed of 14.3 m/s. Whe
Roman55 [17]

Answer:

T = 4517.48 N

Explanation:

It is given that,

Average power of the motor, P_1=2.74\times 10^4\ W

Speed of the boat, v_1=14.3\ m/s

Force or tension acting on the motor at this point is given by :

P=T\times v

T=\dfrac{P_1}{v_1}

T=\dfrac{2.74\times 10^4}{14.3}

T = 1916.08 N

Average power generated by the engine, P_2=9.2\times 10^4\ W

Force or tension acting on the motor at this point is given by :

P=T\times v

T=\dfrac{P_2}{v_2}

T=\dfrac{9.2\times 10^4}{14.3}

T = 6433.56 N

So, the tension in the tow rope that is pulling the skier is, T = 6433.56 N - 1916.08 N = 4517.48 N

4 0
3 years ago
I need help ASAP!!!!<br> Which diagram BEST represents a convection heating current?
Marina86 [1]
Its the first one with the circle and the arrows going around it
5 0
3 years ago
Read 2 more answers
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