Answer:
Explanation:
The weight of some mass is defined as the product of mass by gravitational acceleration. In this way using the following formula we can find the weight.
where:
w = weight [N]
m = mass = 0.06 [kg]
g = gravity acceleration = 10 [N/kg]
Therefore:
By Hooke's law we know that the force in a spring can be calculated by means of the following expression.
where:
k = spring constant [N/m]
x = deformed distance = 6 [cm] = 0.06 [m]
We can find the spring constant.
Since we use the same spring on the moon and the same mass, the constant of the spring does not change, the same goes for the mass.
Since this force is equal to the weight, we can now determine the gravitational acceleration.
Let's call the constant acceleration a.
At a time t, its speed will thus be v(t)=a*t+v0 where v0 is its initial speed, here 10 m/s. Hence v(t)=a*t+10.
From there we can deduce the position P(t)=a*t^2/2+10t+p0 where p0 is the initial position, here 0.
Hence P(t)=a*t^2/2+10t
Let's call T the time at which it's at 50 m/s, we know that P(T)=225m and that v(T)=50 m/s hence a*T+10=50 thus a=40/T and P(T)=(40/2+10)T=30T
Hence T=225/30=7.5
It took 7.5 seconds
Answer:
8.136×10⁻⁵ J
Explanation:
Applying,
Q = Cv................ Equation 1
Where Q = Charge on the capacitor, v = voltage of the battery, C = capacitance of the capacitor.
From the question,
Given: C = 6.78μF = 6.78×10⁻⁶ F, v = 12 V
Substitute these values into equation 1
Q = (6.78×10⁻⁶ )(12)
Q = 8.136×10⁻⁵ J
Hence the charge on the capacitor is 8.136×10⁻⁵ J
Answer: 888.45 K or 615.3 °c
Explanation:
According to Gay Lussacs law which states that at constant volume, pressure of an ideal gas is directly proportional to it's absolute temperature.
P/T = Constant
Therefore, P1/T1 = P2/T2
P1 = 6.7 atm
T1= 23°c = 273.15 + 23 = 296.15K
Since P2 is tripled, then,
P2 = 6.7 x 3= 20.1 atm
T2 = (20.1 x 296.15) ÷ 6.7
T2 = 888.45 K
Or in celcius 615.3°c