Answer: car B has travelled 4times as far as Car A
d=vi*t+1/2at^2
No initial velocity so equation becomes;
d=1/2at^2 and the acceleration is the same between both only time is different;
Car A d=1/2a(1)^2
Car B d=1/2a(2)^2
Car A d= 1^2=1
Car B d= 2^2=4
Car B d=4*Car A
So car B has travelled 4 times as far as car A
Answer:

Explanation:
Given
,
,
,
The tension of the spring is



The force in the spring is equal to centripetal force so


But Fc is also
Fc=KxΔr

Replacing



total distance is

D.all of the above is the answer for this question