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4 years ago

What can be found by counting the number of troughs per second in a wave diagram

Physics

2 answers:

zysi [14]4 years ago

4 0

Frequency,................

frutty [35]4 years ago

3 0

Answer: By counting the number of troughs per second frequency can be calculated.

Explanation:

Frequency of the wave is defined as number of cycles occurring in one second. By counting the number of troughs per second we can calculate frequency of the wave

Amplitude of the wave is defined as maximum displace of the particle from its means position is known as Amplitude.

Wavelength of the wave is defined as distance between two successive crests or troughs.

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In most cases, letters of reconmendation are required for addmission to?

kykrilka [37]

Answer:

Get your recommenders to mention diverse achievements. ...

Help your recommenders with relevant info. ...

The letter should always include examples of things you did. ...

The letter should show how you improved over time. ...

The tone of the letter should not be too dry.

8 0

3 years ago

If a quantity of heat equal to the magnitude of the change in mechanical energy of the water goes into the water, what is its in

Flauer [41]

Increase in temperature of water = 0.53 °C
Explanation:
Change in mechanical energy = Potential energy
Potential energy = mgh
Mass, m = Mass of 1 L water = 1 kg
Acceleration due to gravity, g = 9.81 m/s²
Height, h = 225 m
Potential energy = 1 x 9.81 x 225 = 2207.25 J
Because of this 2207.25 J water gets heated.
Heat energy, E = mcΔT
Mass, m = Mass of 1 L water = 1 kg
Specific heat of water, c = 4200 J/kg/C
Energy, E = 2207.25 J
Change in temperature, ΔT = ?
Substituting
2207.25 = 1 x 4200 x ΔT
ΔT = 0.53 °C
Increase in temperature of water = 0.53 °C

3 0

3 years ago

PLEASE HELP , THOSE ARE ALL THE ANSWERS!

insens350 [35]

Answer:

I don't understand

Explanation:

7 0

3 years ago

Read 2 more answers

Which cell part are red blood cells missing

12345 [234]

They lack a cell nucleus.

3 0

4 years ago

A girl weighing 50 kgf wears sandals of pencil heel of area of cross section 1 cm^2, stands on the floor.An elephant weighing 20

Klio2033 [76]

Answer:

$\boxed{{\boxed{\blue{ 12.5}}}}$

Explanation:

Given, for girl : Weight or force;

$\rm \: F_1 = 50 \: kgf$

Area of both heels;

$\rm \: A_1 = \; 2 ×1 \; cm^2 = 2 \: cm^2$

$\rm \: Pressure \: P_1 = \cfrac{F_1}{ A_1 } = \dfrac{50 \: kgf}{2 \: cm {}^{2} } = 25 \: kgf \: cm {}^{ - 1}$

For elephant, Weight = Force $\rm F_2$ = 2000 kg•f

Area of 4 feet;

$\rm \: A_2 = \; 4 \times 250 \; cm^2 = 1000 \: cm^2$

$\rm \: Pressure \: P_2 = {F_2}/{A_2} \; = \cfrac{2 \cancel{0 00 }\: kgf}{1 \cancel{000} \: cm^2} = 2 \: kgf \: { \:cm}^{- 1}$

Now;

$\rm = \dfrac{Pressure \: Exerted \: by \: the \: Girl}{Pressure \: exerted \: by \: the \: elephant}$

$= \rm \: P_1/P_2$

$\implies \rm\cfrac{25 \: kgf \: \: cm {}^{ - 2} }{2 \: kgf \: cm {}^{ - 2} } = \rm\cfrac{25 \: \cancel{kgf \: \: cm {}^{ - 2}} }{2 \: \cancel{ kgf \: cm {}^{ - 2}} } = \boxed{12.5}$

Thus, the girl's pointed heel sandals exert 12.5 times more pressure P than the pressure P exerted by the elephant.

I aspire this helps!

3 0

2 years ago