All categories

3 years ago

What can be found by counting the number of troughs per second in a wave diagram

Physics

2 answers:

zysi [14]3 years ago

4 0

Frequency,................

frutty [35]3 years ago

3 0

Answer: By counting the number of troughs per second frequency can be calculated.

Explanation:

Frequency of the wave is defined as number of cycles occurring in one second. By counting the number of troughs per second we can calculate frequency of the wave

Amplitude of the wave is defined as maximum displace of the particle from its means position is known as Amplitude.

Wavelength of the wave is defined as distance between two successive crests or troughs.

You might be interested in

Ok these are my last points say hi if u want brainliest

lawyer [7]

Answer:

Explanation:

5 0

3 years ago

Read 2 more answers

A girl runs once around a circular track with a radius of 100m at speed of 10m/s.

goblinko [34]

Answer:

0 m

Explanation:

Displacement is the shortest distance from one ppont to another. Here, the girl returns to the same spot after running. Hence, displacement is 0 m.

5 0

3 years ago

Can there be situation when velocity is constant but speed is not

klasskru [66]

Answer:

no I don’t think there can be so my answer is No.

Okay then yes sorry that I must have gotten it wrong before.

Explanation:

4 0

2 years ago

Read 2 more answers

A ball hits a wall horizontally at 6m/s and rebounces at 4.4m/s the ball is in contact with wall for 0.04 sec. what is the accel

Svetlanka [38]

Answer:

Acceleration (a) = 40 m/s²

Explanation:

Given:

Initial velocity (u) = 6 m/s

Final velocity (v) = 4.4 m/s

Time taken (t) = 0.04sec

Find:

Acceleration (a) = ?

Computation:

We know that,

⇒ v = u + at

⇒ a = (v - u) / t

⇒ Acceleration (a) = (4.4 - 6) / 0.04

⇒ Acceleration (a) = (-1.6) / 0.04

Acceleration (a) = 40 m/s²

8 0

3 years ago

A 3.0-kg mass and a 5.0-kg mass hang vertically at the opposite ends of a rope that goes over an ideal pulley. If the masses are

irga5000 [103]

Answer:

The time taken will be 0.553 seconds.

Explanation:

We should start off by finding the force exerted by the rope on the 3kg weight in this case.

Weight of 5kg mass = 5 * 9.81 = 49.05 N

Weight of 3kg mass = 3 * 9.81 = 29.43 N

The force acting upward on the 3kg mass will equal the weight of the 5kg mass. Thus the resultant force acting on the 3kg mass is:

Total force = 49.05 - 29.43 = 19.62 N (upwards)

We can now find the acceleration:

F = m * a

19.62 = 3 * a

a = 6.54 m/s^2

We now use the following equation of motion to get the time taken to travel 1 meter:

$s=u*t+\frac{1}{2} (a*t^2)$

$1=0*t+\frac{1}{2} (6.54*t^2)$

t = 0.553 seconds

4 0

3 years ago