What can be found by counting the number of troughs per second in a wave diagram

Physics

2 answers:

zysi [14]3 years ago

4 0

Frequency,................

frutty [35]3 years ago

3 0

Answer: By counting the number of troughs per second frequency can be calculated.

Explanation:

Frequency of the wave is defined as number of cycles occurring in one second. By counting the number of troughs per second we can calculate frequency of the wave

Amplitude of the wave is defined as maximum displace of the particle from its means position is known as Amplitude.

Wavelength of the wave is defined as distance between two successive crests or troughs.

You might be interested in

An object is falling downward at a rate of 25 m/s. Two seconds later, what is its acceleration?

zhenek [66]

acceleration times time falling

25*2

50 m*s^-1

6 0

3 years ago

Two electrons in a vacuum exert force of F = 3.8E-09 N on each other. They are then moved such that they are separated by x = 8.

iren [92.7K]

Answer:

F_n = 5.65E-11 N

d = 1.20682E-31 m

Explanation:

F = 3.8E-09 N

where

m = Mass of electron = 9.109E−31 kilograms

G = Gravitational constant = 6.67E-11 m³/kgs²

x = Distance between them

$F=G\frac{m^2}{x^2}\\\Rightarrow 3.8E-09=G\frac{m^2}{x^2}$

For $F_n$

$F_n=G\frac{m^2}{x^2}\\\Rightarrow F_n=G\frac{m^2}{(8.2x)^2}\\\Rightarrow F_n=G\frac{m^2}{67.24x^2}$

Dividing the above equations we get

$\frac{F}{F_n}=\frac{G\frac{m^2}{x^2}}{G\frac{m^2}{67.24x^2}}\\\Rightarrow \frac{F}{F_n}=67.24\\\Rightarrow F_n=\frac{F}{67.24}\\\Rightarrow F_n=\frac{3.8E-09}{67.24}\\\Rightarrow F_n=5.65E-11\ N$

F_n = 5.65E-11 N

$F=G\frac{m^2}{x^2}\\\Rightarrow x=\sqrt{\frac{Gm^2}{F}}\\\Rightarrow x=\sqrt{\frac{G}{F}}m\\\Rightarrow x=\sqrt{\frac{6.67E-11}{3.8E-09}}9.109E-31\\\Rightarrow x=1.20682E-31\ m$