Question

Jane performed the following trials in an experiment.

Answer 1

Answer:

d. The heat absorbed in Trial 2 is about 18420 J greater than the heat absorbed in Trial 1 (16740 J).

Explanation:

• The amount of heat absorbed by water (Q) can be calculated from the relation:

Q = m.c.ΔT.

where, Q is the amount of heat absorbed by water,

m is the mass of water,

c is the specific heat capacity of water (c = 4.186 J/g °C),

ΔT is the temperature difference (final T - initial T).

• For trial 1:

m = 80.0 g, c = 4.18 J/g °C, ΔT = 65.0 °C – 15.0 °C = 50.0 °C

∴ Q = m.c.ΔT = (80.0 g)(4.18 J/g °C)(50.0 °C) = 16740 J.

• For trial 2:

m = 80.0 g, c = 4.18 J/g °C, ΔT = 65.0 °C – 10.0 °C = 55.0 °C

∴ Q = m.c.ΔT = (80.0 g)(4.18 J/g °C)(55.0 °C) = 18420 J.