A 25 N force is applied to a 1.4 kg mass on level ground. If a 5 N frictional force is present between the surface and the objec
1 answer:
Given parameters:
Force applied to the mass = 25N
Mass of the body = 1.4kg
Frictional force = 5N
Unknown:
Acceleration of the object = ?
Solution:
The net force on the object;
Fapplied - Frictional force = net force (m x a)
m is the mass of the body
a is the acceleration
Input the parameters and solve;
25 - 5 = 1.4 x a
1.4a = 20
a = = 14.3m/s²
The magnitude of the acceleration of the object is 14.3m/s²
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Answer:
The magnitude of the electrostatic force is 120.85 N
Explanation:
We can use Coulomb's law to find the electrostatic force between the down quarks.
In scalar form, Coulomb's law states that for charges and
separated by a distance d, the magnitude of the electrostatic force F between them is:
where is Coulomb's constant.
Taking the values:
and knowing the value of the Coulomb's constant:
Taking all this in consideration: