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Vlada [557]
4 years ago
10

A forklift does 450 J of work to lift a 150 N hot tub. How high is the hot tub lifted? Round your answer to the nearest whole nu

mber.
The hot tub is lifted BLANK m.
Physics
2 answers:
OLEGan [10]4 years ago
7 0

Answer:

The hot tub is lifted  3 m.

vivado [14]4 years ago
5 0
There are already 2 givens, hence we can do direct substitution to get the answer. To make the process simpler, derive the distance formula from the Work formula.

Work = Force x Distance

Distance = \frac{Work}{Force}


Work is 450J while the force is 150N hot tub

To get the proper units, get the equivalent of Joule to eliminate newton. A joule Is equal to 1 N-m

Distance = \frac{450N-m}{150N}
Distance = 3m

Hence, the hot tub is lifted 3 meters.
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Please help with this and explain it,if you can.
vladimir2022 [97]

Answer:

displacement at 45 s  =  30

                           65 s  = 50

So the average speed over the interval from 45 s to 65 s is

(50 - 30) cm / 20 s = 1 cm / sec

As a check an average speed of 1 cm / sec for 20 sec will produce a

displacement of 1 cm / sec * 20 sec = 20 cm  or from 30 to 50 cm

4 0
3 years ago
A glider with mass m = 0.230 kg sits on a frictionless horizontal air track, connected to a spring with force constant k = 4.50
loris [4]

Answer

given,

mass of glider = 0.23 Kg

spring constant = k = 4.50 N/m

spring stretched to 0.130 m

The springs potential energy =

 U = \dfrac{1}{2}kx^2

 U = \dfrac{1}{2}\times 4.5 \times 0.13^2

        U = 0.038 J

at x = 0,the only energy will be kinetic .

 \dfrac{1}{2}mv^2=0.038

 \dfrac{1}{2}\times 0.23 \times v^2=0.038

         v² = 0.3304

         v = 0.575 m/s

displacement of the glider

      using conservation of energy

 \dfrac{1}{2}mv^2=\dfrac{1}{2}kx^2

 x =v\sqrt{\dfrac{m}{k}}

 x =3\times \sqrt{\dfrac{0.23}{4.5}}

        x = 0.678 m

8 0
3 years ago
A stone is dropped into a well. The sound of the splash is heard 6.25 s later. What is the depth of the well? (Take the speed of
Naya [18.7K]

Answer:

depth of well is 163.30 m

Explanation:

Given data

speed of sound = 343 m/s

timer = 6.25 s

to find out

depth of well

solution

let us consider depth d

so equation will be

depth = 1/2 ×g ×t²    ..............1

and

depth = velocity of sound × time    .................2

here we have given time 6.25 that is sum of 2 time

when stone reach at bottom that time

another is sound reach us after stone strike on bottom

so time 1 + time 2 = 6.25 s

so from equation 1  and 2 we get

1/2 ×g ×t² = velocity of sound × time

1/2 ×9.8 × t1² = 343 × (6.25 - t1 )

t1 = 5.77376 sec

so height = 1/2 ×g ×t²

height = 1/2 ×9.8 × (5.773)²

height = 163.30 m

3 0
4 years ago
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soldier1979 [14.2K]

Answer:

marblebrainiest plz\c cmarble

Explanation:

8 0
3 years ago
Read 2 more answers
Write equations for both the electric and magnetic fields for an electromagnetic wave in the red part of the visible spectrum th
NeTakaya

Answer:

Explanation:

General equation of the electromagnetic wave:

E(x, t)= E_0sin[\frac{2\pi}{\lambda}(x-ct)+\phi ]

where

\phi = Phase angle, 0

c = speed of the electromagnetic wave, 3 × 10⁸

\lambda = wavelength of electromagnetic wave, 698 × 10⁻⁹m

E₀ = 3.5V/m

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E(x, t)= 3.5sin[\frac{2\pi}{6.98\times10^{-7}}(x-3\times 10^8t)]\\\\E(x, t)= 3.5sin[{9 \times 10^6}(x-3\times 10^8t)]\\\\E(x, t)= 3.5sin[{9 \times 10^6x-2.7\times 10^{15}t)]

Magnetic field Equation

B(x, t)= B_0sin[\frac{2\pi}{\lambda}(x-ct)+\phi ]

Where B₀= E₀/c

B_0 = \frac{E_0}{c} = \frac{3.5}{3\times10^8}=1.2 \times 10^{-8}T

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6 0
3 years ago
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