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HACTEHA [7]
4 years ago
6

Light of wavelength 500nm shines on a pair of slits. This produces an interference pattern on a screen 2.00m behind the slits. M

easuring from the center of the pattern, we find that the fifth dark spot is 4.00cm away. What is the spacing between the slits
Physics
1 answer:
grandymaker [24]4 years ago
7 0

Answer:

The  value is  d = 0.000125 \  m

Explanation:

From the question we are told that

   The  wavelength is  \lambda  =  500 \  nm =  500 *10^{-9 } \  m

    The  distance is of  the screen is  D =  2.0 \ m

    The  width of the fifth dark spot is y  =  4.00 \  cm  =  0.04 \  m

Generally the width of a fringe is mathematically represented as

           y =  \frac{ n  *  \lambda  *  D }{d }

=>        0.04  =  \frac{ 5  * 500 *10^{-9}  *  2 }{d}

=>        d =  \frac{ 5  * 500 *10^{-9}  *  2 }{0.04}

=>        d = 0.000125 \  m

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