Question

Light of wavelength 500nm shines on a pair of slits. This produces an interference pattern on a screen 2.00m behind the slits. Measuring from the center of the pattern, we find that the fifth dark spot is 4.00cm away. What is the spacing between the slits

Answer 1

Answer:

The  value is  $d = 0.000125 \ m$

Explanation:

From the question we are told that

   The  wavelength is  $\lambda = 500 \ nm = 500 *10^{-9 } \ m$

    The  distance is of  the screen is  $D = 2.0 \ m$

    The  width of the fifth dark spot is $y = 4.00 \ cm = 0.04 \ m$

Generally the width of a fringe is mathematically represented as

           $y = \frac{ n * \lambda * D }{d }$

=>        $0.04 = \frac{ 5 * 500 *10^{-9} * 2 }{d}$

=>        $d = \frac{ 5 * 500 *10^{-9} * 2 }{0.04}$

=>        $d = 0.000125 \ m$