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Daniel [21]
3 years ago
14

What is an electrically charged atom? A. ion B. isotope C. molecule D. compound

Chemistry
2 answers:
Leokris [45]3 years ago
8 0
Hey!


ANSWER:
An electrically charged atom is an ion.

Hope this helps!


— Lindsey Frazier ♥️
Xelga [282]3 years ago
7 0

Answer: Option (A) is the correct answer.

Explanation:

When a neutral atom loses an electron then it acquires a negative charge and if a neutral atom gains an electron then it acquires a positive charge. Hence, an ion is formed in both the cases.

For example, sodium on losing an electron become Na^{+} ion.

An isotope is defined as the specie which contains same number of protons but different number of neutrons.

For example, ^{14}_{7}N and ^{15}_{7}N are isotopes.

A molecule is defined as a substance that contains chemically combined two or more number of atoms of an element.

For example, Cl_{2} is a molecule.

Whereas a compound is defined as a substance in which different atoms of different elements chemically combine together in a fixed ratio by mass.

For example, H_{2}O is a compound.

Thus, we can conclude that an ion is an electrically charged atom.

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How many atoms are in 3.2 pg of Ca? The molar mass of Ca is 40.08<br> g/mol.
anyanavicka [17]

Answer:

4.81×10¹⁰ atoms.

Explanation:

We'll begin by converting 3.2 pg to Ca to grams (g). This can be obtained as follow:

1 pg = 1×10¯¹² g

Therefore,

3.2 pg = 3.2 pg × 1×10¯¹² g / 1 pg

3.2 pg = 3.2×10¯¹² g

Therefore, 3.2 pg is equivalent to 3.2×10¯¹² g

Next, we shall determine the number of mole in 3.2×10¯¹² g of Ca. This can be obtained as follow:

Mass of Ca = 3.2×10¯¹² g

Molar mass of Ca = 40.08 g/mol

Mole of ca=.?

Mole = mass /molar mass

Mole of Ca = 3.2×10¯¹² / 40.08

Mole of Ca = 7.98×10¯¹⁴ mole.

Finally, we shall determine the number of atoms present in 7.98×10¯¹⁴ mole of Ca. This can be obtained as illustrated below:

From Avogadro's hypothesis,

1 mole of Ca contains 6.02×10²³ atoms.

Therefore, 7.98×10¯¹⁴ mole of Ca will contain = 7.98×10¯¹⁴ × 6.02×10²³ = 4.81×10¹⁰ atoms.

Therefore, 3.2 pg of Ca contains 4.81×10¹⁰ atoms.

7 0
3 years ago
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