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valina [46]
3 years ago
6

What theory is used to explain the behavior of particles in gases?

Physics
2 answers:
My name is Ann [436]3 years ago
7 0

Kinetic Molecular Theory is the final answer! ::)

KonstantinChe [14]3 years ago
4 0

kinetic molecular theory


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What is the centripetal acceleration of the earth as it travels around the sun when Earth has an orbital radius of 1.5 x 10^11 m
masya89 [10]

Answer: 0.0058 m/s^{2}

Explanation:

Centripetal acceleration a_{C} is calculated by the following equation:

a_{C}=\frac{V^{2}}{r}

Where:

V=29.7 \frac{km}{h} \frac{1000 m}{1 km}=29700 m/s is the Earth's orbital speed

r=1.5(10)^{11} m is the orbital radius

a_{C}=\frac{(29700 m/s)^{2}}{1.5(10)^{11} m}

a_{C}=0.0058 m/s^{2}

4 0
3 years ago
Match the phrase with the term. How hard the blood pushes on the inside of the blood vessels is called . The total amount of blo
taurus [48]

Answer:

How hard the blood pushes on the inside of the blood vessels is called? BLOOD PRESSURE

The total amount of blood the heart pumps in one minute is called ?

CARDIAC OUTPUT

When blood vessels open wider during exercise, they are said to ?

DILATE

How many times your heart beats in one minute is called ?

HEART RATE

The force that can put unhealthy tension on the heart as it is pumping is called ?

BLOOD PRESSURE

The amount of blood the heart pumps out in one beat is called?

STROKE VOLUME

Explanation:

4 0
3 years ago
How to make a tangram with paper?
sattari [20]
Just follow these simple steps:
Fold a rectangular piece of paper so that a square is formed. ...
Cut the square into two triangles.
Take one triangle and fold it in half. ...
Take the other triangle and crease it in the middle. ...
Fold the trapezoid in half and fold again. ...
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3 0
3 years ago
A 4.79 g bullet moving at 642.3 m/s penetrates a tree trunk to a depth of 4.35 cm. Use work and energy considerations to find th
vladimir1956 [14]

Answer:

Force, F=2.27\times 10^4\ N

Explanation:

Given that,

Mass of the bullet, m = 4.79 g = 0.00479 kg

Initial speed of the bullet, u = 642.3 m/s

Distance, d = 4.35 cm = 0.0435 m

To find,

The magnitude of force required to stop the bullet.

Solution,

The work energy theorem states that the work done is equal to the change in its kinetic energy. Its expression is given by :

F.d=\dfrac{1}{2}m(v^2-u^2)

Finally, it stops, v = 0

F.d=-\dfrac{1}{2}m(u^2)

F=\dfrac{-mu^2}{2d}

F=\dfrac{-0.00479\times (642.3)^2}{2\times 0.0435}

F = -22713.92 N

F=2.27\times 10^4\ N

So, the magnitude of the force that stops the bullet is 2.27\times 10^4\ N

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3 years ago
Todo sistema heterogêneo é bifásico
strojnjashka [21]
I don't understand the language.....
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3 years ago
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