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kakasveta [241]
3 years ago
9

CAN SOMEONE HELP PLEASE!!!!!!!!!!!!!!!!!!!!!

Chemistry
1 answer:
aalyn [17]3 years ago
4 0

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How many atoms are present in 0.0350 mol of barium phosphate
lesya692 [45]
There are 3 Barium, 2 Phosphorus and 8 Oxygen in Barium Phosphate (Ba3(PO4)2, making 13 units. Multiply 0.0350 mol given by 13 and then you get 0.455 mol. Since they want atoms, multiply 0.455 by Avogadro's number (0.455 x 6.023 x 1023) and you get 2.74 atoms of barium phosphate. 
3 0
3 years ago
Consider the reaction: 2clf3(g) + 2nh3(g) → n2(g) + 6hf(g) + cl2(g) when calculating the δh°rxn, why is the δhf° for n2 not impo
Leni [432]

<span>Actually, the heat of reaction hrxn s calculated by taking the sum of the heats of formation of the products minus the sum of the heats of formation of the reactants. However, at heat of formations of pure elements at atmospheric conditions is zero, therefore the hf of N2 is not important since it is zero anyway.</span>

8 0
3 years ago
a sample of gold required 2.1200j of heat to melt it from room temperature, 22.0 degrees celsius to its melting point, 1064.4 de
ElenaW [278]

Mass of Gold = 267.165 ×  0.01552494829

⇒ 4.1477228099

The amount of heat(q) required to raise m grams of a substance-specific C from T1 to T2 is given by

q=m C (T2-T1) ........1

Given : q= 2.1200 J

the initial temperature of gold, T1 = 22.0Celcius

the final temperature of gold, T2 = 1064.4Celcius

specific heat of gold = 0.131

putting values in eq 1:

⇒ 2.1200 = m × 0.131 × (1064.4-22)

⇒ 2.1200 = m × 0.131 × 1042.4

⇒ 2.1200 / 136.5544

⇒ 0.01552494829

Since 1g= 0.01552494829 Pounds

Mass of Gold = 267.165 ×  0.01552494829

⇒ 4.1477228099

Learn more about temperature here: brainly.com/question/11464844

#SPJ9

7 0
1 year ago
Which situation describes why a rock sinks in water?
stepladder [879]

Answer:

b

Explanation:

7 0
2 years ago
Write balanced chemical equations for the sequence of reactions that oxalic acid can undergo when it's dissolved in water.
Mashcka [7]

Answer and Explanation:

The balanced chemical equations are as follows:

The chemical formula of oxalic is  H_2C_2O_4

In the case when oxalic acts reacted with the water so here the oxalic acid eliminates one proton that leads to the development of mono acids

After that, the second step derives that when oxalic acid is in aqueous solution eliminates other proton so it represent the polyprotic acid

Now the chemical equations are as follows:

Elimination of one proton

H_2C_2O_4(aq)+H_2O(l)  \rightarrow H_2C_2O_4^-(aq) + H_3O^+(aq)

Now the elimination of other proton

HC_2O_4^-(aq)+H_2O(l)  \rightarrow C_2O_4^2^-(aq) + H_3O^+(aq)

7 0
2 years ago
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