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3 years ago

By using kekule's structure,explain the hybrid resonance of benzene

Chemistry

1 answer:

OLEGan [10]3 years ago

5 0

<h2><u>Answer:</u></h2>

So as to picture this, we should think about the situation of electrons in the obligations of benzene. This sort of structure is known as a reverberation mixture of the benzene particle. Actually, neither structure truly exists. Delocalisation must be clarified utilizing a larger amount of hypothesis than single and twofold bonds.

Reverberation of Benzene. The swaying twofold bonds in the benzene ring are clarified with the assistance of reverberation structures according to valence bond hypothesis. All the carbon iotas in the benzene ring are sp2 hybridized.

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The solid dissolves quickly is a chemical or physical reaction

Vladimir79 [104]

Answer:

i think it is chemical wait no physical

Explanation:

4 0

3 years ago

Decane (C10H22) is used in diesel. The combustion for decane follows the equation: 2 C10H22 + 31 O2 à 20 CO2 + 22 H2O. Calculate

creativ13 [48]

The mass of water produced is 792 grams by the combustion of 568 grams of decane.

Given:

Combustion of 568 grams of decane with 2979 grams of oxygen.

$2 C_{10}H_{22 }+ 31 O_2 \rightarrow 20 CO_2 + 22 H_2O$

To find:

The mass of water produced by combustion of 568 grams of decane.

Solution:

Mass of decane = 568 g

Moles of decane :

= $\frac{568 g}{142 g/mol}=4 mol$

Mass of oxygen gas = 2976 g

Moles of oxygen gas:

= $\frac{2976 g}{32 g/mol}=93 mol$

$2 C_{10}H_{22 }+ 31 O_2 \rightarrow 20 CO_2 + 22 H_2O$

According to reaction, 2 moles of decane reacts with 31 moles of oxygen, then 4 moles of decane will react with:

$=\frac{31}{2}\times 4mol=62\text{ mol of}O_2$

But according to the question, we have 93.0 moles of oxygen gas which is more than 62 moles of oxygen gas.

So, this means that oxygen gas is present in an excessive amount. Which simply means:

Oxygen gas is an excessive reagent.
Decane is a limiting reagent.
Decane being limiting reagent will be responsible for the amount of water produced after the reaction.

According to reaction, 22 moles of water is produced from 2 moles of decane, then 4 moles of decane will produce:

$=\frac{22}{2}\times 4mol=44\text{mol of }H_2O$

Mass of 44 moles of water ;

$=44mol\times 18g/mol=792g$

792 grams of water is produced by the combustion of 568 grams of decane.

Learn more about limiting reagent and excessive reagent here:

brainly.com/question/14225536?referrer=searchResults

brainly.com/question/7144022?referrer=searchResults

3 0

3 years ago

The reusable booster rockets of the U.S. space shuttle use a mixture of aluminum and ammonium

kolezko [41]

Answer:

The mass will be 100

Explanation:

4 0

3 years ago

In which of the following situations is the greatest amount of work accomplished?

Dahasolnce [82]

<span>work = force x distances </span>

<span>A - moving 2 newton's up 0.6 meter = 1.2 joules
B - moving 4 newton's up 0.6 meter = 2.4 joules
C - moving 6 newton's up 0.3 meter = 1.8 joules
D - moving 9 newton's up 0.3 meter = 2.7 joules
The greatest amount of work is in example D.
</span>

<span>
D is your answer. </span>

7 0

4 years ago

Read 2 more answers

Write the following numbers in ordinary notation.

adoni [48]

Answer:

Explanation:

The values are given in scientific notation.

Scientific notation:

Scientific notation is the way to express the large value in short form.

The number in scientific notation have two parts.

. The digits (decimal point will place after first digit)

× 10 ( the power which put the decimal point where it should be)

for example the number 6324.4 in scientific notation will be written as = 6.3244 × 10³

Ordinary notation:

The ordinary notation is expended notation of writing the numerical values which is normal way. The numbers are written as they are, without the power of 10.

a) 7.356 ×10⁻⁶ km

0.000007356 km

b) 3.02 ×10⁻⁵ g

0.0000302 g

c) 8.348 ×10⁶ Kg

8,348,000 kg

d) 7.6352 ×10⁻³ s

0.0076352 s

4 0

3 years ago