Acetic acid is an weak acid. According to Henderson-Hasselbalch equation for a buffer consist of weak acid (acetic acid) and its conjugate base (acetate)-

$pH=pK_{a}(acetic acid)+log[\frac{mmol of CH_{3}COO^{-}}{mmol of CH_{3}COOH }]$

Here pH is 5.31, $pK_{a}$ (acetic acid) is 4.74 and number of mmol of acetic acid is 10 mmol.

Plug in all the values in the above equation:

$5.31=4.74+log[\frac{mmol of CH_{3}COO^{-}}{10}]$

or, mmol of $CH_{3}COO^{-}$ = 37

So 37 mmol of acetate need to add to this solution.

3 0

3 years ago

A student heats a liquid on a burner. What happens to the portion of liquid that first begins to warm?

Natalija [7]

I believe it becomes less dense, bc when you heat something it’s molecules spread further apart.

8 0

3 years ago

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Calculate the molarity of a solution made by adding 120 g of naoh (40.00 g/mol) to enough water to make 500.0 ml of solution. g

sertanlavr [38]

An: Calculate the molarity of a solution made by adding 120 g of NaOH (40.00 g/mol) to enough water to make 500.0 mL of solution. a) 4.0 M b) 6.0 M c) 1.0 ...

Explanation:

7 0

2 years ago

What are some of the activities performed during experiment

aev [14]

Answer:

nobmelonisegxfixcyctGkchkcigdtidtifyoc

6 0

3 years ago

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