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Gnom [1K]
4 years ago
13

What is the energy released from nuclear fuels inside a nuclear reactor used for

Physics
1 answer:
belka [17]4 years ago
6 0
Each time a uranium nucleus splits<span> up it releases energy and three neutrons. If all the neutrons are allowed to be absorbed by other uranium nuclei the chain reaction will spiral out of control causing an explosion. To control the energy released in the reactor moveable control rods are placed between the fuel rods.</span>
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During cellular respiration what is broken down into usable energy for the cell
denis23 [38]
Im sure what is broken down is glucose.

(Anyone feel free to correct me if you think I'm wrong)
6 0
4 years ago
Pls can anyone solve this​
gayaneshka [121]

Answer:

3 pls give me brainliest

Explanation:

8 0
3 years ago
A 20 g ball of clay traveling east at 4.5 m/s collides with a 45 g ball of clay traveling north at 2.0 m/s. You may want to revi
german

Answer:

The ball travels with a speed of 1.96 m/s in a North East direction

Explanation:

Based on the law of conservation of linear momentum, we have that

m_{1}v_{1}+m_{2}v_{2}=(m_{1}+m_{2})v

Since this problem involves motion in both the x and y coordinates, we will solve it in the separate coordinates, and then find the resultant as our answer.

Momentum in the x- direction

in the x direction, v_{2}= 0. this makes m_{2}v_{2}=0

hence we have

20\times4.5=65v_{x}

v_{x}=1.385m/s

Momentum in the y- direction

in the y direction, v_{1}= 0. this makes m_{1}v_{1}=0

hence we have

45\times2.0=65v_{y}

v_{y}=1.385m/s

The resultant of the two vectors can be found using Pythagoras' theorem

v=\sqrt{1.385^{2}+1.385^{2}} =1.959

The direction of the resultant vector is found as

Tan^{-1}(\frac{1.385}{1.385})=45degrees

Hence the ball moves with a velocity of 1.96m/s in a North East direction

7 0
3 years ago
A solid disc with a radius of 5.00 m and a mass of 20.0 kg is initially at rests and lies on the plane of the paper. A smaller s
drek231 [11]

Answer:

Explanation:

This problem is based on conservation of angular momentum.

moment of inertia of larger  disc I₁ = 1/2 m r²  , m is mass and r is radius of disc . I

I₁ = .5 x 20 x 5²

= 250 kgm²

moment of inertia of smaller  disc I₂ = 1/2 m r²  , m is mass and r is radius of disc . I

I₂ = .5 x 10 x 2.5²

= 31.25 kgm²

3500 rmp = 3500 / 60 rps

n = 58.33 rps

angular velocity of smaller disc ω₂ = 2πn

= 2π x 58.33

= 366.3124 rad /s

applying conservation of angular momentum

I₂ω₂  = ( I₁ +I₂) ω  , ω is the common angular velocity

31.25 x 366.3124 = ( 250 +31.25) ω

ω = 40.7 rad / s .

4 0
3 years ago
ANSWER ASAP PLEASEEE Kendra wonders what would happen if the oceans did not exist on Earth. Based on her understanding of the oc
Cloud [144]

Answer:

that there would be more clouds.

Explanation:

one of the cycles is precipitation. without water there would be no rain and clouds are what causes the rain to come down

7 0
4 years ago
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