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3 years ago

What is the charge of an ion that contains 21 protons and 19 electrons?

Chemistry

1 answer:

Nikolay [14]3 years ago

5 0

1 proton = 1 positive charge
1 electron = 1 negative charge

+21-19= <u>+3</u>

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Consider the chemical reaction in equilibrium.

Zarrin [17]

This is an application of Le Chatlier's principle: What happens when we add a reagent to one side of an equation? The reaction will shift to the other side. So heat is a reactant and we're adding more of it, the reaction must therefore, shift to the right ( or the products side).

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3 years ago

Read 2 more answers

What is the mass of 3.20x10^23 formula units of iron (III) oxide (Fe2O3)?

yaroslaw [1]

The mass of iron (III) oxide (Fe2O3) : 85.12 g

<h3>Further explanation</h3>

Given

3.20x10²³ formula units

Required

The mass

Solution

1 mole = 6.02.10²³ particles

Can be formulated :

N = n x No

N = number of particles

n = mol

No = 6.02.10²³ = Avogadro's number

mol of Fe₂O₃ :

$\tt n=\dfrac{3.2.10^{23}}{6.02.10^{23}}=0.532$

mass of Fe₂O₃ (MW=160 g/mol)

$\tt mass=mol\times MW=0.532\times 160=85.12~g$

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2 years ago

A candy bar has a total mass of 75.0 grams. In a calorimetry experiment, a 1.0-g sample of this candy bar was burned in a calori

geniusboy [140]

<span>a. 3.1 calories in heat were released by the burning candy bar sample b. The energy value of the sample was 3.1 Cal/g c.The total caloric content of the candy bar is 232.5 Calories, derived by multiplying the total mass of the candy bar by its fuel value per gram</span>

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3 years ago

2. How many grams of water can be warmed from 25.0°C to 37.0°C by the addition of 8,064 calories?

sertanlavr [38]

Answer:

672 g

Explanation:

We can calculate the mass of water that can be warmed from 25.0°C to 37.0°C by the addition of 8,064 calories using the following expression.

$Q = c \times m \times \Delta T$

where,

c: specific heat of the water

m: mass

ΔT: change in the temperature

$m = \frac{Q}{c \times \Delta T } = \frac{8,064cal}{(1cal/g. \° C) \times (37.0 \° C - 25.0 \° C) } = 672 g$

The mass of water that can be warmed under these conditions is 672 grams.

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3 years ago

3. (1 p) How many oxygen atoms are in 2.5 moles of nitrogen dioxide?

uranmaximum [27]

1.505X10^24 hope this helped :)

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3 years ago