A. Strong Acid vs. Strong Base
By using electric carssss
T = 14400 s
26.5 x 14400=381600 C
381600/96500=3.95 Faradays
Cu2+ + 2e- = Cu
3.95 faradays ( 1 mol/ 2 Faradays) = 1.97
mass = 1.97 x 63.55 g/mol=125 g
moles Au = 33.1 / 196.967 g/mol=0.168
Au+ + 1e- = Au
0.168 ( 1 Faraday/ 1mol)= 0.168 Faraday
0.168 x 96500=16217 Coulombs
16217 / 5.00=3243 s => 54 min
Answer:
0.16 M hydrocyanic acid + 0.15 M sodium cyanide
Explanation:
For a buffer system to be regarded as good, it must contain conjugate acid base pair in the solution. A buffer can be made by mixing a weak acid with its conjugate base.
In a good buffer system, their must be a close concentration of the acid base conjugates so as to ensure that the buffering capacity has the same neutralization capacity for any strong acid base system.