Question

A 3.0 N force and a 5.0 N force are acting in opposite directions on the same 5.0 kg ball. What is the magnitude of the acceleration of the ball?

Answer 1

F(net)=ma

(5-3)=5a
2=5a
a=0.4

Hope I can help u

Answer 2

Answer:

The acceleration of the ball is $0.4\ m/s^2$

Explanation:

It is given that,

Force acting on the object, F₁ = 3 N (right side)

Force acting on the object, F₂ = 5 N (left side)

Mass of the ball, m = 5 kg

We need to magnitude of the acceleration of the ball. First of all, we need to find the net force acting on the ball.

$F_{net}=F_2-F_1$

$F_{net}=5-3=2\ N$

Now let a is the acceleration of the ball. It can be calculated using second law of motion as :

$a=\dfrac{F{net}}{m}$

$a=\dfrac{2\ N}{5\ kg}$

$a=0.4\ m/s^2$

So, the acceleration of the ball is $0.4\ m/s^2$. Hence, this is the required solution.