Answer:
energy known as the latent heat of vaporization is required to break the hydrogen bonds. At 100 °C, 540 calories per gram of water are needed to convert one gram of liquid water to one gram of water vapour under normal pressure.
Explanation:energy known as the latent heat of vaporization is required to break the hydrogen bonds. At 100 °C, 540 calories per gram of water are needed to convert one gram of liquid water to one gram of water vapour under normal pressure.
Answer:
1
Recall that at STP, 1 mole of any ideal gas occupies 22.4 liters. Volume O2 gas = 0.0510 moles O2 x 22.4 L/mole = 1.14 liters (3 sig.
Explanation:
hope this helps
Hello!
Take for example the heating of water.
When heating liquid water from room temperature (25 °C) to the boiling point (100 °C), adding heat results in a direct increase in the temperature. This kind of heat is called sensible heat, because we can sense the effect of the added energy.
But when you reach 100 °C, there is a phase change from liquid to vapour, and the added heat is used to produce the phase change, and no increase in temperature is observed, only the phase change. This kind of heat is called latent heat.
Have a nice day!
Answer: The pH of solution is 10.
The pOH of the solution is 4.
Explanation:
pH is the negative logarithm of concentration of hydrogen ion.
As given concentration of acidic solution is
. Therefore, pH of the solution is calculated as follows.
![pH = -log [H^{+}]\\= -log (1.00 \times 10^{-10})\\= 10](https://tex.z-dn.net/?f=pH%20%3D%20-log%20%5BH%5E%7B%2B%7D%5D%5C%5C%3D%20-log%20%281.00%20%5Ctimes%2010%5E%7B-10%7D%29%5C%5C%3D%2010)
The relation between pH and pOH is as follows.
pH + pOH = 14
pOH = 14 - pH
= 14 - 10
= 4
Thus, we an conclude that pH of solution is 10 and pOH of the solution is 4.