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marta [7]
2 years ago
14

An engine manufacturer makes the claim that the engine they have developed will, on each cycle, take 100 j of heat out of boilin

g water at 100°c, do mechanical work of 80 j, and exhaust 20 j of heat at 10°c. what, if anything, is wrong with this claim? the efficiency of this engine is greater than the ideal carnot cycle efficiency.
Physics
1 answer:
Digiron [165]2 years ago
8 0

hot reservoir temp 100

cold res temp= 10

eff = (1- cold/hot)x100%

by temperatures eff = (1-10/100)x100 ... by heat transfers eff = (1-20/100)x100

the claims seem to disagree

eff = 90% .... very high. 80%

a carnot may be about 70% If it is reversible and is between two reservoirs


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\boxed{v=\frac {V}{\sqrt {2}}}

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We know that frequency of simple pendulum follows that f=\frac {1}{2\pi} \sqrt {\frac {g}{l}}

Now, the speed of the father will be V=Lf= L\times (\frac {1}{2\pi} \sqrt {\frac {g}{l}}) while for the child the speed will be v=\frac {L}{2}\times (\frac {1}{2\pi} \sqrt {\frac {g}{0.5l}})

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\frac {V}{v}=\frac {\frac {L}{2}\times (\frac {1}{2\pi} \sqrt {\frac {g}{0.5l}})}{ L\times (\frac {1}{2\pi} \sqrt {\frac {g}{l}})}\\\frac {V}{v}=\frac {\sqrt {2}}{2}\\\boxed{v=\frac {V}{\sqrt {2}}}

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Where 'V' is the potential difference across the circuit and 'I' is the current in the circuit.

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4 0
2 years ago
The energy from 0.015 moles of octane was used to heat 250 grams of water. The temperature of the water rose from 293.0 K to 371
arsen [322]

Answer : The correct option is, (B) -5448 kJ/mol

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First we have to calculate the heat required by water.

q=m\times c\times (T_2-T_1)

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q = heat required by water = ?

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c = specific heat capacity of water = 4.18J/g.K

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T_2 = final temperature of water = 371.2 K

Now put all the given values in the above formula, we get:

q=250g\times 4.18J/g.K\times (371.2-293.0)K

q=81719J

Now we have to calculate the enthalpy of combustion of octane.

\Delta H=\frac{q}{n}

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Now put all the given values in the above formula, we get:

\Delta H=\frac{-81719J}{0.015mole}

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Therefore, the enthalpy of combustion of octane is -5448 kJ/mol.

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3 years ago
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