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Setler [38]
3 years ago
9

A water wave is generated in a ripple tank by an oscillator that vibrates 50 times in 30 seconds. a given trough of the wave tra

vels 50.0 cm in 15 seconds. what is the wavelength of the water wave? produce all your workings.
Physics
1 answer:
Dovator [93]3 years ago
8 0

There are 50 vibrations in 30 seconds

So frequency is given by

f = \frac{N}{T}

f = \frac{50}{30}

Now we can also find the speed of wave

speed is defined as ratio of distance and time

speed = \frac{distance}{time}

speed = \frac{0.50}{15}

v = 0.033 m/s

now to find the wavelength we can use the relation between frequency, wavelength and speed

this relation is given as

speed = frequency * wavelength

0.033 = \frac{5}{3}* \lambda

\lambda = 0.02 m = 2 cm

so the wavelength is 2 cm

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Answer: Plz mark me brainlest.

The pressure in the bottom of the glass is defined as P= (pv)g/A.

  • V is the Volume.
  • A is the Area.
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5 0
3 years ago
A block of gelatin is 120mm by 120mm by 40mm whrn unstressed. A force of 49N is applied tangentially to the upper surface causin
Inessa05 [86]

Answer:

The shearing stress is 10208.3333 Pa

The shearing strain is 0.25

The shear modulus is 40833.3332 Pa

Explanation:

Given:

Block of gelatin of 120 mm x 120 mm by 40 mm

F = force = 49 N

Displacement = 10 mm

Questions: Find the shear modulus, Sm = ?, shearing stress, Ss = ?, shearing strain​, SS = ?

The shearing stress is defined as the force applied to the block over the projected area, first, it is necessary to calculate the area:

A = 40*120 = 4800 mm² = 0.0048 m²

The shearing stress:

Ss=\frac{F}{A} =\frac{49}{0.0048} =10208.3333Pa

The shearing strain is defined as the tangent of the displacement that the block over its length:

SS=tan\theta =\frac{Displacement}{L}  =\frac{10}{40} =0.25

Finally, the shear modulus is the division of the shearing stress over the shearing strain:

Sm=\frac{10208.3333}{0.25} =40833.3332Pa

6 0
3 years ago
To suck lemonade of density 1040 kg/m3 up a straw to a maximum height of 4.94 cm, what minimum gauge pressure (in atmospheres) m
Lady bird [3.3K]

Answer:

The minimum gauge pressure is 0.4969 atm.

Explanation:

Given that,

Density = 1040 kg/m³

Height = 4.94 cm

We need to calculate the pressure

Using formula of pressure

P_{g}=\rho g h

Where, \rho=density

h = height

Put the value into the formula

P_{g}=1040\times9.8\times4.94

P_{g}=50348.48\ Pa

Pressure in atmospheres

1\ atm =101.3\ kPa

P_{g}=\dfrac{50348.48}{101325}

P_{g}=0.4969\ atm

Hence, The minimum gauge pressure is 0.4969 atm.

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Let the sphere is having charge Q and radius R

Now if the proton is released from rest

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so the proton will move by above speed and

here Q = charge on the sphere

R = radius of sphere

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