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Naily [24]
3 years ago
5

Use the following picture to answer questions #6 and 7. Consider that after the snowboarder starts down from the hill from point

A, she travels all the way to the end of the path.
6. Standing still at the top of the hill at point A, what kind of energy (potential and/or kinetic) would the snowboarder have? How do you know?

7. Explain the energy conversion from point C to point B. Make sure to include a description of both kinetic and potential energy.
Chemistry
1 answer:
STALIN [3.7K]3 years ago
4 0
Remeber:

Kinectic energy = [1/2]mv^2
Potential energy = m.g[h - h0]

6. When the snowboarder is still at the top, she does not have kinetic energy, given that the speed is zero.

There, at the top, the potential energy is maximum, given that the height, h - h0, is the highest.

So, ar the topo she only has potential energy.

7. From that point, the snowboarder, starts to gain velocity; is has started a process of conversion of potential energy to kinetic energy. More velocity, less height, more kinetic ener energy and less ptential energy.

At the very bottom, when she has reached the heigth of reference, h0, the term [h - h0] becomes zero, then the potential energy has dissapeared and all the energy has been transformed into kinetic energy; the speed and the kinetic energy are maximum.
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What would be the effect on the nucleus of an atom if it emitted one alpha particle and one gamma ray
Oksana_A [137]
Unstable, radioactive atom emits alpha and gamma ray to transform into a stable atom.

Emitting an alpha particle, decreases the mass number by four and atomic number by two.
Emitting gamma ray reduces the excess energy of the radioactive atom.
4 0
3 years ago
The goal of this experiment is to separate a mixture of two unknown compounds into individual components and to identify the com
kolbaska11 [484]

Answer: Ethyl Ethanoate can be used as a developing solvent. It’s safer.

Explanation:Di ethyl ether should be carefully used because it’s highly flammable and intoxicating when inhaled and can cause explosions because of its high reactivity to air and light.

3 0
3 years ago
What is one benefit and one negative of the Gulf Stream
luda_lava [24]

This is a benefit I’m not sure if a negative

This strong current of warm water influences the climate of the east coast of Florida, keeping temperatures there warmer in the winter and cooler in the summer than the other southeastern states. Since the Gulf Stream also extends toward Europe, it warms western European countries as well.

6 0
2 years ago
A mouse is placed in a sealed chamber with air at 769.0 torr. This chamber is equipped with enough solid KOH to absorb any CO2 a
svlad2 [7]

<u>Answer:</u> The amount of oxygen gas consumed by mouse is 0.202 grams.

<u>Explanation:</u>

We are given:

Initial pressure of air = 769.0 torr

Final pressure of air = 717.1 torr

Pressure of oxygen = Pressure decreased = Initial pressure - Final pressure = (769.0 - 717.1) torr = 51.9 torr

To calculate the amount of oxygen gas consumed, we use the equation given by ideal gas which follows:

PV=nRT

where,

P = pressure of the gas = 51.9 torr

V = Volume of the gas = 2.20 L

T = Temperature of the gas = 292 K

R = Gas constant = 62.364\text{ L. Torr }mol^{-1}K^{-1}

n = number of moles of oxygen gas = ?

Putting values in above equation, we get:

51.9torr\times 2.20L=n\times 62.364\text{ L. Torr }mol^{-1}K^{-1}\times 292K\\\\n=\frac{51.9\times 2.20}{62.364\times 292}=0.0063mol

To calculate the mass from given number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Moles of oxygen gas = 0.0063 moles

Molar mass of oxygen gas = 32 g/mol

Putting values in above equation, we get:

0.0063mol=\frac{\text{Mass of oxygen gas}}{32g/mol}\\\\\text{Mass of oxygen gas}=(0.0063mol\times 32g/mol)=0.202g

Hence, the amount of oxygen gas consumed by mouse is 0.202 grams.

5 0
3 years ago
If aluminum is diffused into a thick slice of silicon with no previous aluminum in it at a temperature of 1100˚C for 8 hours, wh
RideAnS [48]

Answer:

8.354 nanometers

Explanation:

To treat a diffusive process in function of time and distance we need to solve  2nd Ficks Law. This a partial differential equation, with certain condition the solution looks like this:

\frac{C_{s}-C{x}}{C_{s}-C_{o}}=erf(x/2\sqrt{D*t})

Where Cs is the concentration in the surface of the solid

Cx is the concentration at certain deep X

Co is the initial concentration of solute in the solid

and erf is the error function

Then we solve right side,

\frac{C_{s}-C{x}}{C_{s}-C_{o}}=\frac{1018atoms/cm3-1016atoms/cm3}{1018atoms/cm3}=0.001964

And we need to look up the inverse error function of 0.001964 resulting in: 0.00174055

Then we solve for x:

x=0.00174055*2*\sqrt{D*t} =0.00174055*2*\sqrt{2*10^{-12}cm^{2}/s*8h*3600s/h}=8.35464*10^{-7}cm

6 0
3 years ago
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