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DanielleElmas [232]
3 years ago
14

Which of the following causes your hands to feel warm when you rub them together?

Physics
2 answers:
Sholpan [36]3 years ago
8 0

Answer:

Friction

Explanation:

Hi there! I'm glad I was able to help you!

Friction would be your best option.

I chose friction as the answer after using the process of elimination.

Normal force, in a simple definition, is basically when nothing happens and an object is sitting on top of another, so the net force is zero. In our case, we're rubbing our hands together, so option A is out of the question.

Spring force, which is much different than normal force, requires the use of an actual spring. It's a force that compresses AND decompresses a spring.

Gravity is the force that keeps us (and other objects), from floating into the air. Gravity is like a giant human magnet!

Finally, the force of friction acts in the complete and total opposite direction of the way an object, any object (in this case, our hands), want to slide. When we rub our hands together, it kind of activates the molecules and stuff inside of them to turn on, or activate, just a little bit quicker than before your hands even touched together. The faster the molecules move, the higher the temperature becomes!

I hope this helped you! Comment below if you have any other questions! :)

tekilochka [14]3 years ago
7 0

Answer:

Friction

Explanation:

<em>Friction causes heat because it forces particles to move at a quicker speed and gain more energy.</em>

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3 years ago
Describe how Newton’s third law applies to the box and the table.
Snowcat [4.5K]

Answer:

the box has vertical force on the table

Explanation:

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A long solenoid has a radius of 2.0 cm and has 700 turns/m. If the current in the solenoid is decreasing at the rate of 8.0 A/s,
Brrunno [24]

Answer:

The magnitude of the induced electric field at a point 2.5 cm from the axis of the solenoid is 8.8 x 10⁻⁵ V/m

Explanation:

given information:

radius, r = 2.0 cm

N = 700 turns/m

decreasing rate, dI/dt = 9.0 A/s

the magnitude of the induced electric field at a point 2.5 cm (r = 2.5 cm = 0.025 m) from the axis of the solenoid?

the magnetic field at the center of solenoid

B = μ₀nI

where

B = magnetic field (T)

μ₀ = permeability (1.26× 10⁻⁶ T.m/A)

n = the number turn per unit length (turn/m)

I = current (A)

dB/dt = μ₀n dI/dt                                           (1)

now we calculate the induced electric field by using

E = \frac{1}{2}r\frac{dB}{dt}  

\frac{dB}{dt} = 2E/r                                                     (2)

where

E = the induced electric field (V/m)

we substitute the firs and second equation, thus

dB/dt = μ₀n dI/dt  

2E/r = μ₀n dI/dt  

E = (1/2) r μ₀n dI/dt

  = (1/2) (0.025) (1.26× 10⁻⁶) (700) (8)

  = 8.8 x 10⁻⁵ V/m

6 0
3 years ago
melvin pulls a sled across level snow with a force of 317 N along a rope that is 33 degrees above the horizont?
tatuchka [14]

Answer: work Melvin did=9000J

Explanation:

Given to complete the question: If the sled moved 33.9m,how much work did Melvin do? Answer in unit of J and round to the nearest thousandth.

W = F ×S

W = 317 × cos 33°×33.9

W=9012.6055J

W=9000J to the nearest thousandth

8 0
3 years ago
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