Bro2 is polar because the rules for overall polarity of Neutral Species Arrangement of Group Linear Trigonal Planar Tetrahedral Trigonal Bipyramidal Octahedral Polarity if atoms on either side of the center atom are different, the species is polar if any group around the central atom is different.
Cl2(s); oxidation number 1 is the incorrect choices in oxidation number.
Explanation:
In the elemental form oxidation state is zero. Here chlorine is present in elemental form so oxidation state is zero.
Oxidation number depends on the number of electrons gained or lost by an atom of the element say in compound formation.
If electron is gained oxidation number becomes negative.
If electron is lost then oxidation number is positive.
If the octet rule is fulfilled that valence shell is filled them atomic number gets zero. Since Cl2 is in neutral state the oxidation number is 0.
Oxidation number in general can be made out by checking the valency of the element as oxidation number is also equal to the valency.
It depends on the process.
Like for example if the process is isothermal(temperature is constant), you can use,
PV = constant or P1V1 = P2V2 where P1V1 are initial conditions and P2V2 are final.
For adiabatic process,
PV^gamma = constant or P1V1 ^gamma = P2V2 ^gamma.
where gamma = Cp
------
Cv
Cp = specific heat at constant pressure and Cv = specific at constant volume.
Value of Gamma will be given in question.
Hope this helps!
<u>Answer:</u> The increase in temperature is 7.14°C
<u>Explanation:</u>
To calculate the change in temperature, we use the equation:
where,
q = heat absorbed = 14.5 kJ = 14500 J (Conversion factor: 1 kJ = 1000 J)
m = mass of water = 485 g g
c = specific heat capacity of water = 4.184 J/g.°C
= change in temperature = ?
Putting values in above equation, we get:
Hence, the increase in temperature is 7.14°C
We are tasked to find the amount of O2 in grams given only the number of moles of oxygen gas. To solve the problem, we need first to calculate the molecular weight of oxygen. Based on the periodic table, elemental oxygen has a molecular weight of 16 g/mol. Thus its molecular weight is,
O2=16.0g/mol (2)=32 g/mol
To solve for the amount of compound oxygen in grams, we have,
O2 (g)=5 mol x 32 g/mol =160 g.
This cancel out the mols both in the numerator and denominator leaving only the g as a unit. Therefore, 5 mols of oxygen is equal to 160 g of oxygen.
