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Reika [66]
3 years ago
15

You do 30 J of work to load a toy dart gun. However, the dart is 10 cm long and feels a frictional force of 10 N while going thr

ough the dart gunâs barrel. What is the kinetic energy of the fired dart?
a. 30 J
b. 29 J
c. 28 J
d. 27 J
Physics
1 answer:
shepuryov [24]3 years ago
6 0

Answer: Option (b) is the correct answer.

Explanation:

The given data is as follows.

         K.E_{1} = 30 J,    l = 10 cm = 0.1 m (as 1 m = 100 cm)

               F = 10 N  

The formula to calculate the work done is as follows.

          W = F \times l

Hence, putting the given values into the above formula as follows.

                W = F \times l

                     = 10 N \times 0.1 m

                     = 1 J

As the dart loses 1 joule of energy when it goes through the barrel. Therefore, the kinetic energy it has when it comes out is calculated as follows.

              K.E = 30 - 1

                    = 29 J

Thus, we can conclude that the kinetic energy of the fired dart is 29 J.

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A flywheel in a motor is spinning at 510 rpm when a power failure suddenly occurs. The flywheel has mass 40.0 kg and diameter 75
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Complete Question

A flywheel in a motor is spinning at 510 rpm when a power failure suddenly occurs. The flywheel has mass 40.0 kg and diameter 75.0 cm . The power is off for 40.0 s , and during this time the flywheel slows down uniformly due to friction in its axle bearings. During the time the power is off, the flywheel makes 210 complete revolutions. At what rate is the flywheel spinning when the power comes back on(in rpm)? How long after the beginning of the power failure would it have taken the flywheel to stop if the power had not come back on, and how many revolutions would the wheel have made during this time?

Answer:

\theta=274rev

Explanation:

From the question we are told that:

Angular velocity \omega=510rpm

Mass m=40.kg

Diameter d 75=>0.75m

Off Time t=40.0s

Oscillation at Power off N=210

Generally the equation for Angular displacement is mathematically given by

 \theta_{\infty}=\frac{w+w_0}{t}t

 w=\frac{2*\theta_{\infty}}{t}-w_0

 w=\frac{28210}{40*(\frac{1}{60})}-510

 w=120rpm

Generally the equation for Time to come to rest is mathematically given by

 t=(\frac{\omega_0}{\omega_0-\omega})t

 t=(\frac{510}{510-120rpm})(40.0)(\frac{1}{60})

 t=0.87min

Therefore Angular displacement is

 \theta =(\frac{120+510}{2})0.87

 \theta=274rev

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3 years ago
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Answer:

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Explanation:

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So, the number of moles of the gas is

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p is the pressure

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