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loris [4]
3 years ago
10

Does protons ,electrons, and neutrons have anything to do with lighting?

Chemistry
1 answer:
antoniya [11.8K]3 years ago
4 0

Answer:

Yes

Explanation:

hope this helps!

 Do you want me to explain?

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ANSWER FAST PLZ 25 POINTS!!!!!!!!!!!!!!!
sp2606 [1]

Answer:

The answer is A, if im not mistaken

8 0
3 years ago
Explain why the nucleus of an atom is positively charged but the overall charge of an atom is neutral
gtnhenbr [62]

Answer:

The nucleus is positively charged because it contains all of the protons however the charge of an atom is neutral because there is an equal amount of protons (positive) and electrons (negative) meaning the opposite charges cancel each other out therefore making the atoms overall charge neutral.

Explanation:

8 0
2 years ago
What occurs when a solid substance dissolves into a liquid? 1 It stays solid and sinks to the bottom of the liquid substance. 2
katrin [286]

Explanation:

When a solid substance is dissolved in a liquid such as water, the intermolecular forces of attraction between the molecules in the solid substance are overcome and they exist as ions in the solution. Hence the answer is 2.

6 0
3 years ago
Explain why neon is monatomic but chlorine is diatomic.
Elza [17]
Chlorine is a halogen and all halogens and oxygen, nitrogen and hydrogen are diatomics
5 0
2 years ago
Read 2 more answers
Which relationship can be used to aid in the determination of the heat absorbed by bomb calorimeter? 
NARA [144]

Answer:

ΔH = q_{p}

Explanation:

In a calorimeter, when there is a complete combustion within the calorimeter, the heat given off in the combustion is used to raise the thermal energy of the water and the calorimeter.

The heat transfer is represented by

q_{com} = q_{p}

where

q_{p} = the internal heat gained by the whole calorimeter mass system, which is the water, as well as the calorimeter itself.

q_{com}  = the heat of combustion

Also, we know that the total heat change of the any system is

ΔH = ΔQ + ΔW

where

ΔH = the total heat absorbed by the system

ΔQ = the internal heat absorbed by the system which in this case is q_{p}

ΔW = work done on the system due to a change in volume. Since the volume of the calorimeter system does not change, then ΔW = 0

substituting into the heat change equation

ΔH = q_{p} + 0

==> ΔH = q_{p}

5 0
3 years ago
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