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3 years ago

Which represents the balanced double displacement reaction between Sodium Chloride (Na+Cl-) and Copper Sulfate (Cu2+(SO4)2-) ?

Chemistry

1 answer:

34kurt3 years ago

6 0

Answer:

The balanced double displacement reaction is as follows.

$2NaCl+CuSO_{4}\rightarrow Na_{2}SO_{4}+CuCl_{2}$

Explanation:

The given reactant has sodium,chloride and copper sulfate ions.

In the double displacement reaction, two ionic compounds exchange their cations.

Sulphate and chloride ions are cations these are exchanged sodium and copper elements.

Hence, the balanced double exchange reaction is as follows.

$2NaCl+CuSO_{4}\rightarrow Na_{2}SO_{4}+CuCl_{2}$

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How much heat is needed to change 5g of ice at 0°C to<br> water at 50°C?

natta225 [31]

Answer:

400cal

Explanation:

Since ice melted at 0 Celesius then the heat gained by ice (latent heat) will melt it so you should substitute in that law

Q=mlf ..where Q is the heat required to convert ice to water , m is the mass of ice and lf is the latent heat of fusion

Q=5∗80=400cal

6 0

3 years ago

What is newly formed land consisting of and arc shaped island chain called?

sweet [91]

A volcanic arc is a chain of volcanoes formed above a subducting plate, positioned in an arc shape as seen from above. Offshore volcanoes form islands, resulting in a volcanic island arc.

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4 years ago

A 3.3 g sample of sodium hydrogen carbonate is added to a solution of acetic acid weighing 10.3 g. The two substances react, rel

Zanzabum

Answer:

1.73g of CO2.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

NaHCO3 + CH3COOH → CH3COONa + H2O + CO2

Next we shall determine the masses of NaHCO3 and CH3COOH that reacted and the mass of CO2 produced from the balanced equation. This is illustrated below:

Molar mass of NaHCO3 = 23 + 1 + 12 + (16x3) = 84g/mol

Mass of NaHCO3 from the balanced equation = 1 x 84 = 84g

Molar mass of CH3COOH = 12 + (3x1) + 12 + 16 + 16 + 1 = 60g/mol

Mass of CH3COOH from the balanced equation = 1 x 60 = 60g

Molar mass of CO3 = 12 + (2x16) = 44g/mol

Mass of CO2 from the balanced equation = 1 x 44 = 44g

From the balanced equation above,

84g of NaHCO3 reacted with 60g of CH3COOH to produce 44g of CO2.

Next, we shall determine the limiting reactant of the reaction. This is illustrated below:

From the balanced equation above,

84g of NaHCO3 reacted with 60g of CH3COOH.

Therefore, 3.3g of NaHCO3 will react with = (3.3 x 60)/84 = 2.36g of CH3COOH.

From the above illustration, we can see that only 2.36g of CH3COOH out of 10.3g given reacted completely with 3.3g of NaHCO3. Therefore, NaHCO3 is the limiting reactant while CH3COOH is the excess reactant.

Finally, can determine the mass of CO2 produced during the reaction.

In this case the limiting reactant will be used because it will produce the mass yield of CO2 as all of it were used up in the reaction. The limiting reactant is NaHCO3 and the mass of CO2 produced is obtained as shown below:

From the balanced equation above,

84g of NaHCO3 reacted to produce 44g of CO2.

Therefore, 3.3g of NaHCO3 will react to produce = (3.3 x 44)/84 = 1.73g of CO2.

Therefore, 1.73g of CO2 is released during the reaction.

7 0

3 years ago

Why do you think many metals are good at conducting electricity?<br> Hurry, please!!!

umka2103 [35]

Answer. Metals are excellent conductors because the atoms in a metal form a matrix through which their outer electrons can move freely. Instead of orbiting their respective metal atoms, they form a "sea" of electrons that surrounds the positively charged atomic nuclei of the interacting metal ions

5 0

3 years ago

The pressure is changed from 500 kPa to 250 kPa. What would you expect the new volume to be if the initial volume is 200 mL?

Romashka [77]

Answer:

<h3>The answer is 400 mL</h3>

Explanation:

The new volume can be found by using the formula for Boyle's law which is

$P_1V_1 = P_2V_2$

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we are finding the new volume

$V_2 = \frac{P_1V_1}{P_2} \\$

So we have

$V_2 = \frac{500000 \times 200}{250000} = \frac{100000000}{250000} = \frac{10000}{25} \\$

We have the final answer as

Hope this helps you

4 0

3 years ago