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34kurt
3 years ago
14

Which represents the balanced double displacement reaction between Sodium Chloride (Na+Cl-) and Copper Sulfate (Cu2+(SO4)2-) ?

Chemistry
1 answer:
34kurt3 years ago
6 0

Answer:

The balanced double displacement reaction is as follows.

2NaCl+CuSO_{4}\rightarrow Na_{2}SO_{4}+CuCl_{2}

Explanation:

The given reactant has sodium,chloride and copper sulfate ions.

In the double displacement reaction, two ionic compounds exchange their cations.

Sulphate and chloride ions are cations these are exchanged sodium and copper elements.

Hence, the balanced double exchange reaction is as follows.

2NaCl+CuSO_{4}\rightarrow Na_{2}SO_{4}+CuCl_{2}

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Law of Conservation of Mass in terms of atoms
VARVARA [1.3K]

No atoms are lost or made during the chemical reaction so the total mass of the products is equal to the total mass of the reactants. In an atom, protons and neutrons contribute to the mass and since the number of them doesn’t change, the mass doesn’t either.

4 0
3 years ago
The ion formed by an atom of sulfur when it gains two electrons is called a:
dolphi86 [110]

Answer:

sulfide ion

Explanation:

however, when non-metalic elements gain electrons to form anions the end of their name is change to "-ide".foe example, a flourin atom gains one electronto become a flouride ion(F`) and sulfur gains two electrons to become a sulfide ion(s^2)

8 0
3 years ago
_________ deficiency is the developing world’s most common cause of preventable brain damage.
aniked [119]
I believe the answer is A. Iron
7 0
3 years ago
A 300 L sample of hydrogen was compressed to a volume of 200 L at STP. If the initial temperature is 35.0 °C,
a_sh-v [17]

Answer:

76.210kPa

Explanation:

\frac{p1v1}{t1}  =  \frac{p2v2}{t2}  \\ p1 =  \frac{p2v2t1}{v1t1} \\ p1 =  \frac{101.325 \times 200 \times 308}{300 \times 273} \\ p1 = 76.210kpa

6 0
2 years ago
sa solution is made by dissolving 26.42 g of (NH4)2SO4 in enough H2O to make 50.00 mL of solution. what is the molarity of the s
krok68 [10]
The answer is 0.2 M.

Molarity is a measure of the concentration of solute in a solution

c = n ÷V<span>
c - concentration of solute,
n - number of moles of solute
V - volume of solution

</span>

We know:

V = 50.00 mL = 0.05 L

c = ?

n = ?


Let's calculate concentration:

c = m/(V * Mr)


The molar mass of <span>(NH4)2SO4 is the sum of atomic masses (Ar) of its elements):
Mr (</span><span>(NH4)2SO4) = 2Ar(N) + 8 Ar(H) + Ar(S) + 4Ar(O)
                           = 2 * 14 + 8 * 1 + 32 + 4 * 16 =
                           = 28 + 8 + 32 + 64 = 
                           = 132 g/mol

c = 26.42 g/ (0.05 L * 132g /mol) =26.42 g/ 6.6 L*g/mol = 4 mol/L = 4 M

Now, calculate molarity:
</span>c = n ÷V
n = c * V
n = 4 mol/L * 0.05 L
n = 0.2 mol
4 0
3 years ago
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