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Crank
2 years ago
14

Which process involved in deep water currents

Chemistry
1 answer:
kolbaska11 [484]2 years ago
4 0
Its convection. i hope this helps please give me brainliest
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Part A Find ΔS∘ for the reaction between nitrogen gas and hydrogen gas to form ammonia: 12N2(g)+32H2(g)→NH3(g) Express your answ
inessss [21]

Answer:

\Delta S^{0} for the given reaction is -99.4 J/K

Explanation:

Balanced reaction: \frac{1}{2}N_{2}(g)+\frac{3}{2}H_{2}(g)\rightarrow NH_{3}(g)

\Delta S^{0}=[1mol\times S^{0}(NH_{3})_{g}]-[\frac{1}{2}mol\times S^{0}(N_{2})_{g}]-[\frac{3}{2}mol\times S^{0}(H_{2})_{g}]

where S^{0} represents standard entropy.

Plug in all the standard entropy values from available literature in the above equation:

\Delta S^{0}=[1mol\times 192.45\frac{J}{mol.K}]-[\frac{1}{2}mol\times 191.61\frac{J}{mol.K}]-[\frac{3}{2}mol\times 130.684\frac{J}{mol.K}]=-99.4J/K

So, \Delta S^{0} for the given reaction is -99.4 J/K

7 0
3 years ago
How much heat is required to raise the temperature of 50.0g of water 13°C<br>​
N76 [4]

Answer:one gram by 1oC

Explanation: you will need to know the value of water's specific heat

3 0
3 years ago
a 10.99g sample of NaBr contains 22.34% Na by mass. Considering the law of constant composition (define proportions), how many g
leonid [27]

Given :

A 10.99 g sample of NaBr contains 22.34% Na by mass.

To Find :

How many grams of sodium does a 9.77g sample of sodium bromine contain.

Solution :

By law of constant composition , in any given chemical compound, the elements always combine in the same proportion with each other.

Therefore , percentage of Na by mass in NaBr will be same for every amount .

Percentage of Na in 9.77 g NaBr is 22.34 % too .

Gram of Na = 9.77\times \dfrac{22.34}{100}=2.18\ g .

Hence , this is the required solution .

7 0
3 years ago
Identify the gas law that applies to the following scenario: If a gas in a closed container is pressurized from 18.0 atm to 14.0
nalin [4]

Answer:

Gay-Lussac's Law

Explanation:

The pressure is directly proportional to the absolute temperature under constant volume. This states the Gay-Lussac's law. The equation is:

P1T2 = P2T1

<em>Where P is pressure and T absolute temperature of 1, initial state and 2, final state of the gas.</em>

<em />

That means the right option is:

- Gay-Lussac's Law

6 0
2 years ago
20. Which of the following are pure substances?
Juliette [100K]
The answer is III and V
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3 years ago
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