A) law of inertia. an object in motion stays in motion
        
             
        
        
        
Answer:
  a =( -0.32 i ^ - 2,697 j ^)  m/s²
Explanation:
This problem is an exercise of movement in two dimensions, the best way to solve it is to decompose the terms and work each axis independently.
 Break down the speeds in two moments
initial
   v₀ₓ = v₀ cos θ
   v₀ₓ = 5.25 cos 35.5
 v₀ₓ = 4.27 m / s
    = v₀ sin θ
 = v₀ sin θ
   = 5.25 sin35.5
= 5.25 sin35.5
  = 3.05 m / s
 = 3.05 m / s
Final
 vₓ = 6.03 cos (-56.7)
 vₓ = 3.31 m / s
  = v₀ sin θ
 = v₀ sin θ
  = 6.03 sin (-56.7)
 = 6.03 sin (-56.7)
  = -5.04 m / s
 = -5.04 m / s
Having the speeds and the time, we can use the definition of average acceleration that is the change of speed in the time order
     a = ( - v₀) /t
 - v₀) /t
     aₓ = (3.31 -4.27)/3 
     aₓ = -0.32 m/s²
      = (-5.04-3.05)/3
 = (-5.04-3.05)/3
     =  -2.697 m/s²
 =  -2.697 m/s²
 
        
             
        
        
        
If  Biker 1 has less mass than Biker 2 it the follows that biker 1 has a greater acceleration than Biker 2.
<h3>What is the Newton second law?</h3>
The Newton second law gives the relationship between the force and the acceleration. We know that; acceleration = Force/mass.
Now if Biker 1 has less mass than Biker 2 it the follows that biker 1 has a greater acceleration than Biker 2.
Learn more about Newton's law:brainly.com/question/27573481
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 The maximum height reached by the ball is 0.46m.
To find the answer, we have to know about the potential energy of a spring mass system.
<h3>How to find the maximum height reached by the ball?</h3>
                        
- We have to find the maximum height reached by the ball.
- Thus, we have the expression for potential energy of a spring mass system and that of gravitational field as,
                              
                     
Thus, we can conclude that, the maximum height reached by the ball is 0.46m.
Learn more about the potential energy here:
brainly.com/question/26962934
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Answer:
121550 J
Explanation:
Parameters given:
Mass, m = 0.34kg
Specific heat capacity, c = 14300 J/kgK
Change in temperature, ΔT = 25K
Heat gained/lost by an object is given as:
Q = mcΔT
Since ΔT is positive in this case and also because we're told that heat was transferred to the hydrogen sample, the hydrogen sample gained heat. Therefore, Q:
Q = 0.34 * 14300 * 25
Q = 121550J or 121.55 kJ