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Sever21 [200]
3 years ago
11

Which statement is correct? Salts are formed by the reaction of bases with water. Most salts are ionic and are soluble in water.

Most salts are insoluble in water and lack electrical charges. Solutions of salt and water do not conduct electricity.
Chemistry
2 answers:
Lorico [155]3 years ago
7 0

Answer:

The correct statement is "most salts are ionic and are soluble in water"

Explanation:

Salts are made up of cation (positively charged species) and anion (negatively charged species). These oppositely charged species are held together by ionic forces.

Water is a polar solvent.Therefore it prefers polar solutes. Salts are therefore likely to be soluble in water.

Acid and base reacts to give salt and water. Hence salts are produced from acid base reaction.

In aqueous solution, cations and anions remain in separated form and therefore free to move. Hence aqueous solution of salt can conduct electricity.

Studentka2010 [4]3 years ago
3 0
<span>Salts are formed by the reaction of bases with water. -  FALSE
</span><span>Most salts are ionic and are soluble in water. -  TRUE
</span><span>Most salts are insoluble in water and lack electrical charges. - FALSE
</span><span>Solutions of salt and water do not conduct electricity. - FALSE

:)</span>
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Property of a substance
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8 0
3 years ago
The copper(I) ion forms a chloride salt (CuCl) that has Ksp = 1.2 x 10-6. Copper(I) also forms a complex ion with Cl-:Cu+ (aq) +
Mnenie [13.5K]

Answer: (a) The solubility of CuCl in pure water is 1.1 \times 10^{-3} M.

(b) The solubility of CuCl in 0.1 M NaCl is 9.5 \times 10^{-3} M.

Explanation:

(a)  Chemical equation for the given reaction in pure water is as follows.

           CuCl(s) \rightarrow Cu^{+}(aq) + Cl^{-}(aq)

Initial:                         0            0

Change:                    +x           +x

Equilibm:                   x             x

K_{sp} = 1.2 \times 10^{-6}

And, equilibrium expression is as follows.

          K_{sp} = [Cu^{+}][Cl^{-}]

       1.2 \times 10^{-6} = x \times x

             x = 1.1 \times 10^{-3} M

Hence, the solubility of CuCl in pure water is 1.1 \times 10^{-3} M.

(b)  When NaCl is 0.1 M,

       CuCl(s) \rightarrow Cu^{+}(aq) + Cl^{-}(aq),  K_{sp} = 1.2 \times 10^{-6}

   Cu^{+}(aq) + 2Cl^{-}(aq) \rightleftharpoons CuCl_{2}(aq),  K = 8.7 \times 10^{4}

Net equation: CuCl(s) + Cl^{-}(aq) \rightarrow CuCl_{2}(aq)

               K' = K_{sp} \times K

                          = 0.1044

So for, CuCl(s) + Cl^{-}(aq) \rightarrow CuCl_{2}(aq)

Initial:                     0.1                 0

Change:                -x                   +x

Equilibm:            0.1 - x                x

Now, the equilibrium expression is as follows.

              K' = \frac{CuCl_{2}}{Cl^{-}}

         0.1044 = \frac{x}{0.1 - x}

              x = 9.5 \times 10^{-3} M

Therefore, the solubility of CuCl in 0.1 M NaCl is 9.5 \times 10^{-3} M.

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Nonamiya [84]

Answer:

A. an equal and opposite reaction force

Explanation:

This means that there is a natural reaction of force

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