Answeill give it a go i guess
Explanation:
Year on Gravestone Thickness at bottom Time of weathering AOW
1758 78.5 258 2.4
1766 82.5 79.6 2.4
1758 78.5 258 2.4
1758 78.5 258 2.4
1758 78.5 258 2.4
1758 78.5 258 2.4
1758 78.5 258 2.4
1758 78.5 258 2.4
1758 78.5 258 2.4
1758 78.5 258 2.4
1758 78.5 258 2.4 nvm got lazy
Answer:
5.59 m/s2
Explanation:
F = 1900 N
m = 340 kg
F = ma
Therefore, a = 1900/340 = 5.59
Answer:
[1, 6, -2]
Explanation:
Given the following :
Initial Position of spaceship : [3 2 4] km
Velocity of spaceship : [-1 2 - 3] km/hr
Location of ship after two hours have passed :
Distance moved by spaceship :
Velocity × time
[-1 2 -3] × 2 = [-2 4 -6]
Location of ship after two hours :
Initial position + distance moved
[3 2 4] + [-2 4 -6] = [3 + (-2)], [2 + 4], [4 + (-6)]
= [3-2, 2+4, 4-6] = [1, 6, -2]
Given:
h = 600 m, the height of descent
t = 5 min = 5*60 = 300 s, the time of descent.
Let a = the acceleration of descent., m/s².
Let u = initial velocity of descent, m/s.
Let t = time of descent, s.
The final velocity is v = 0 m/s because the helicopter comes to rest on the ground.
Note that u, v, and a are measured as positive upward.
Then
u + at = v
(u m/s) + (a m/s²)*(t s) = 0
u = - at
u = - 300a (1)
Also,
u*t + (1/2)at² = -h
(um/s)*(t s) + (1/2)(a m/s²)*(t s)² = 600
ut + (1/2)at² = 600 (2)
From (1), obtain
-300a +(1/2)(a)(90000) = -600
44700a = -600
a = - 1.3423 x 10⁻² m/s²
From (1), obtain
u = - 300*(-1.3423 x 10⁻²) = 4.03 m/s
Answer:
The acceleration is 0.0134 m/s² downward.
The initial velocity is 4.0 m/s upward.
1. Mass number = Protons + Neutrons
Mass number = 26 + 32 = 58
2. Let the element be Xy
58Xy26
3. The proton number of Strontium is 38.
Mass = 38 + 50 = 88
4. 88Sr38
5. Let the atom be Ab
72Ab32
