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vodomira [7]
3 years ago
10

What is the wavelength of a radio photon from an "am" radio station that broadcasts at 1160 kilohertz?what is its energy?

Physics
1 answer:
netineya [11]3 years ago
7 0
Given:
f = 1160 kHz = 1160 x 10³ Hz
The velocity is c = 3 x 10⁸ m/s, the velocity of light (approximmately).

Calculate the wavelength, λ.
c = fλ
λ = c/f = (3 x 10⁸ m/s)/(1160 x 10³ 1/s) = 258.62 m

Answer: 258.6 m
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A 49 kg person is being dragged in their sleeping bag to the lake by a 593 N
crimeas [40]

Answer:

f = 485.62 N

Explanation:

Since, the bag is moving with some acceleration. Hence, the unbalanced force will be given as:

Unbalanced Force = Horizontal Component Applied Force - Frictional Force

Unbalanced Force = Fx - f

But, from Newtons Second Law of Motion:

Unbalanced Force = ma

comparing the equations:

ma = Fx - f

f = F Cos θ - ma

where,

f = frictional force  = ?

F = Applied force  = 593 N

m = mass of person = 49 kg

a = acceleration = 0.57 m/s²

θ = Angle with horizontal = 30°

Therefore,

f = (593 N)(Cos 30°) - (49 kg)(0.57 m/s²)

f = 513.55 N - 27.93 N

<u>f = 485.62 N</u>

6 0
3 years ago
On android phones, up to four apps can be pinned to the __________ at the bottom of the screen.
Paladinen [302]
That is called a Dock 

4 0
3 years ago
Consider the two moving boxcars in Example 5. Car 1 has a mass of m1 = 65000 kg and a velocity of v01 = +0.80 m/s. Car 2 has a m
Amiraneli [1.4K]

Answer:

1.034m/s

Explanation:

We define the two moments to develop the problem. The first before the collision will be determined by the center of velocity mass, while the second by the momentum preservation. Our values are given by,

m_1 = 65000kg\\v_1 = 0.8m/s\\m_2 = 92000kg\\v_2 = 1.2m/s

<em>Part A)</em> We apply the center of mass for velocity in this case, the equation is given by,

V_{cm} = \frac{m_1v_1+m_2v_2}{m_1+m_2}

Substituting,

V_{cm} = \frac{(65000*0.8)+(92000*1.2)}{92000+65000}

V_{cm} = 1.034m/s

Part B)

For the Part B we need to apply conserving momentum equation, this formula is given by,

m_1v_1+m_2v_2 = (m_1+m_2)v_f

Where here v_f is the velocity after the collision.

v_f = \frac{m_1v_1+m_2v_2}{m_1+m_2}

v_f = \frac{(65000*0.8)+(92000*1.2)}{92000+65000}

v_f = 1.034m/s

8 0
3 years ago
A 1000 kg car moves as speed from 10 m/s to 30 m/s in 20 seconds. What is the average speed ? What is the acceleration ? What is
8_murik_8 [283]

Answer: divide

Explanation:

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3 years ago
Pen and ink manufacturers are asked to submit their new ink formulations to what database?
Ilia_Sergeevich [38]
The international ink library.
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3 years ago
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