Answer: Option A: The number of trees sampled.
The accuracy can be understood as how close is the measured value to the true value. The aim is to monitor the population size of the insect pest in a 50 square kilometer. Random trees are selected, and number of eggs and larvae are counted. So, the measured value would be closer to actual value when the number of trees sampled are increased. More the number of trees sampled, less would be the chances of error and the accuracy of the estimate would increase.
Answer:
377 m
Explanation:
number of turns, N = 65
θ = 36°
B1 = 200 micro Tesla
B2 = 600 micro tesla
t = 0.4 s
induced emf, e = 80 mV
Let a be the side of the square coil.
![e=\frac{d\phi }{dt}=NA\frac{dB}{dt}\times Sinθ](https://tex.z-dn.net/?f=e%3D%5Cfrac%7Bd%5Cphi%20%7D%7Bdt%7D%3DNA%5Cfrac%7BdB%7D%7Bdt%7D%5Ctimes%20Sin%CE%B8)
![0.080=\frac{65\times a^{2}\times Sin36\times\left ( 600 - 200 \right )\times 10^{-6}}{0.4}](https://tex.z-dn.net/?f=0.080%3D%5Cfrac%7B65%5Ctimes%20a%5E%7B2%7D%5Ctimes%20Sin36%5Ctimes%5Cleft%20%28%20600%20-%20200%20%5Cright%20%29%5Ctimes%2010%5E%7B-6%7D%7D%7B0.4%7D)
![0.080=0.038a^{2}](https://tex.z-dn.net/?f=0.080%3D0.038a%5E%7B2%7D)
a = 1.45 m
Total length of the wire, L = N x 4a = 65 x 4 x 1.45 = 377 m
Thus, the length of the wire is 377 m.
To perform a drug lookup to ensure that the new compound has been added to the computer system properly we have to select the new from the toolbar at the top of the screen
<h3>What is a computer system?</h3>
A computer system is a collection of computers, related hardware, and related software. The central processing unit (CPU), memory, input/output, and storage devices are the four main components of a computer system. To produce the desired result, all of these parts operate in concert as a single unit.
Selecting the new from the toolbar at the top of the screen will allow us to run a drug lookup to make sure the new compound has been properly added to the computer system.
Therefore the correct answer is the option C
Learn more about the computer system here
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Double
Explanation:
Since the period T of a pendulum is given by
![T = 2\pi \sqrt{\dfrac{l}{g}}](https://tex.z-dn.net/?f=T%20%3D%202%5Cpi%20%5Csqrt%7B%5Cdfrac%7Bl%7D%7Bg%7D%7D)
By increasing the length of the pendulum by 4, the period becomes
![T' = 2\pi \sqrt{\dfrac{4l}{g}} = 2\left(2\pi \sqrt{\dfrac{l}{g}}\right) = 2T](https://tex.z-dn.net/?f=T%27%20%3D%202%5Cpi%20%5Csqrt%7B%5Cdfrac%7B4l%7D%7Bg%7D%7D%20%3D%202%5Cleft%282%5Cpi%20%5Csqrt%7B%5Cdfrac%7Bl%7D%7Bg%7D%7D%5Cright%29%20%3D%202T)
You can see that the period doubles when we increase the length by a factor of 4.
Answer:
x=22.33m
Explanation:
Kinematics equation for constant deceleration:
![x =v_{o}*t - 1/2*at^{2}=8.9*6.3-1/2*1.70*6.3^{2}=22.33m](https://tex.z-dn.net/?f=x%20%3Dv_%7Bo%7D%2At%20-%201%2F2%2Aat%5E%7B2%7D%3D8.9%2A6.3-1%2F2%2A1.70%2A6.3%5E%7B2%7D%3D22.33m)