All categories

3 years ago

How do you find the range of a data set

Physics

1 answer:

GaryK [48]3 years ago

4 0

Range is only the highest value subtracted from the lowest value unless of your talking about line plots

You might be interested in

Explain why it is esaier to climb a mountain on a zigzag path rather than one straight up the side. is your increase in gravitat

pogonyaev

Answer:

More work done with less power

The increase in gravitational energy is the same as the height which is a function of gravitational energy is the same in both cases

Explanation:

Climbing the mountain in zigzag pattern is easier because

1. The time it takes to climb increases so that the required power or rate of doing work decreases

2. Climbing in zigzag pattern affords the use of leverages by the sides

3. Similar mechanical power gain and efficiency from using a drive screw instead of a nail to fasten items together can be achieved

The increase in gravitational energy is the same gravitational energy ~ mass × gravity ×height

6 0

3 years ago

Give the 7 color harmonies

notsponge [240]

Answer:

Complementary colors.

Split complementary colors.

Analogous colors.

Triadic harmonies.

Tetradic harmonies.

Monochromatic harmonies.

Explanation:

7 0

2 years ago

Read 2 more answers

What force keeps the outside of a bicycle wheel from flying off?

4vir4ik [10]

Answer:

Centripetal force

Explanation:

8 0

2 years ago

Light from two lasers is incident on an opaque barrier with a single slit of width 4.0 x 10^-4 m. One laser emits light of wavel

Sergio [31]

Answer:

a) y = 2.4 x 10⁻³ m = 0.24 cm

b) y = 3.2 x 10⁻³ m = 0.32 cm

Explanation:

The formula of Young's Double Slit experiment will be used here:

$y = \frac{\lambda L}{d}\\\\$

where,

y = distance between dark spots = ?

λ = wavelength

L = distance of screen = 2 m

d = slit width = 4 x 10⁻⁴ m

a) FOR λ = 480 nm = 4.8 x 10⁻⁷ m:

$y = \frac{(4.8\ x\ 10^{-7}\ m)(2\ m)}{4\ x\ 10^{-4}\ m}$

y = 2.4 x 10⁻³ m = 0.24 cm

a) FOR λ = 640 nm = 6.4 x 10⁻⁷ m:

$y = \frac{(6.4\ x\ 10^{-7}\ m)(2\ m)}{4\ x\ 10^{-4}\ m}$

y = 3.2 x 10⁻³ m = 0.32 cm

7 0

2 years ago

Air bags are designed to deploy in 10 ms. Given that the air bags expand 20 cm as they deploy, estimate the acceleration of the

joja [24]

As it is given that the air bag deploy in time

$t = 10 ms = 0.010 s$

total distance moved by the front face of the bag

$d = 20 cm = 0.20 m$

Now we will use kinematics to find the acceleration

$d = v_i*t + \frac{1}{2}at^2$

$0.20 = 0 + \frac{1}{2}a*0.010^2$

$0.20 = 5 * 10^{-5}* a$

$a = 4000 m/s^2$

now as we know that

$g = 10 m/s^2$

so we have

$a = 400g$

so the acceleration is 400g for the front surface of balloon

3 0

2 years ago