Question

How many moles NaOH are contained in 65.0 mL of a 2.20 M solution of NaOH in H2O?

Answer 1

The   number  of  moles  of  NaOh that  are    contained  in  65ml  of   2.20M  solution  NaOh  in H2o  is  calculated  using  the  below  formula


moles  =  molarity  x  volume  /1000

that  is     65 x2.20  /1000=  0.143  moles

Answer 2

Explanation:

Molarity is defined as number of moles divided by volume in liter.

Mathematically,       Molarity = $\frac{no. of moles}{Volume in liter}$

Since, it is known that 1 L equals 1000 ml so 65.0 mL equals 0.065 L.

Therefore, it is given that volume is 0.065 L and molarity is 2.20 M. Hence, calculate number of moles as follows.

            Molarity = $\frac{no. of moles}{Volume in liter}$

    Number of moles = $Molarity \times Volume in liter$

                                  = $2.20 M \times 0.065 L$

                                  = 0.143 mol

Thus, we can conclude that there are 0.143 moles NaOH are contained in 65.0 mL of a 2.20 M solution of NaOH in $H_2O$.