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san4es73 [151]
3 years ago
6

How many moles NaOH are contained in 65.0 mL of a 2.20 M solution of NaOH in H2O?

Chemistry
2 answers:
saw5 [17]3 years ago
0 0
The   number  of  moles  of  NaOh that  are    contained  in  65ml  of   2.20M  solution  NaOh  in H2o  is  calculated  using  the  below  formula


moles  =  molarity  x  volume  /1000

that  is     65 x2.20  /1000=  0.143  moles

lakkis [162]3 years ago
0 0

Explanation:

Molarity is defined as number of moles divided by volume in liter.

Mathematically,       Molarity = \frac{no. of moles}{Volume in liter}

Since, it is known that 1 L equals 1000 ml so 65.0 mL equals 0.065 L.

Therefore, it is given that volume is 0.065 L and molarity is 2.20 M. Hence, calculate number of moles as follows.

            Molarity = \frac{no. of moles}{Volume in liter}

    Number of moles = Molarity \times Volume in liter

                                  = 2.20 M \times 0.065 L

                                  = 0.143 mol

Thus, we can conclude that there are 0.143 moles NaOH are contained in 65.0 mL of a 2.20 M solution of NaOH in H_2O.

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shutvik [7]

Answer:

The right answer is "3 g".

Explanation:

Given:

Initial mass substance,

M_0=24 \ g

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Thus, the above is the correct answer.

8 0
3 years ago
ether has a density of 0.736 g/cm^3 at 20 degrees C. what is the volume, in liters, of 225.0 grams of ether?
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D = m / V

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3 years ago
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2 years ago
The solubility of lead(ii) chloride is 0.45 g/100 ml of solution. what is the ksp of pbcl2? 4.9 × 10-2 1.7 × 10-5 8.5 × 10-6 4.2
Artyom0805 [142]
Answer:
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Explanation:
1- get the number of moles of PbCl2:
number of moles = mass / molar mass
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2- get the concentration of Pb2+:
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molarity = (1.618 * 10^-3) / (0.1) = 0.0162 M

3- getting concentration of Cl-:
<span>PbCl2(s) <==> Pb2+(aq) + 2Cl-(aq) 
</span>We can note that:
For a certain amount of Pb2+ formed, twice this amount of Cl- is formed.
This means that:
for 0.0162 M of Pb2+, 2*0.0168 = 0.0324 M of Cl- is formed

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3 years ago
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