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3 years ago

How many moles NaOH are contained in 65.0 mL of a 2.20 M solution of NaOH in H2O?

2 answers:

0 0

The number of moles of NaOh that are contained in 65ml of 2.20M solution NaOh in H2o is calculated using the below formula

moles = molarity x volume /1000

that is 65 x2.20 /1000= 0.143 moles

lakkis [162]3 years ago

0 0

Explanation:

Molarity is defined as number of moles divided by volume in liter.

Mathematically, Molarity = $\frac{no. of moles}{Volume in liter}$

Since, it is known that 1 L equals 1000 ml so 65.0 mL equals 0.065 L.

Therefore, it is given that volume is 0.065 L and molarity is 2.20 M. Hence, calculate number of moles as follows.

Molarity = $\frac{no. of moles}{Volume in liter}$

Number of moles = $Molarity \times Volume in liter$

= $2.20 M \times 0.065 L$

= 0.143 mol

Thus, we can conclude that there are 0.143 moles NaOH are contained in 65.0 mL of a 2.20 M solution of NaOH in $H_2O$ .

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ElenaW [278]

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