How many moles NaOH are contained in 65.0 mL of a 2.20 M solution of NaOH in H2O?
2 answers:
Explanation:
Molarity is defined as number of moles divided by volume in liter.
Mathematically, Molarity =
Since, it is known that 1 L equals 1000 ml so 65.0 mL equals 0.065 L.
Therefore, it is given that volume is 0.065 L and molarity is 2.20 M. Hence, calculate number of moles as follows.
Molarity =
Number of moles =
=
= 0.143 mol
Thus, we can conclude that there are 0.143 moles NaOH are contained in 65.0 mL of a 2.20 M solution of NaOH in .
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Answer:
Total Kcal energy produced in the catabolism of mannoheptulose = 1184 Kcal
Explanation:
The molecular formula of mannoheptulose is C₇H₁₄O₇.
The structure is as shown in the attachment below.
Number of C-C bonds present in mannoheptulose = 6
Number of C-H bonds present in mannoheptulose = 8
Since the each C-C bond contains 76 Kcal of energy,
Amount of energy present in six C-C bonds = 6 * 76 = 456 Kcal
Also, since each C-H bond contains 91 Kcal of energy;
amount of energy present in eight C-H bonds = 8 * 91 = 728 Kcal
Total Kcal energy produced in the catabolism of mannoheptulose = 456 + 728 = 1184 Kcal
