All categories

4 years ago

How many moles NaOH are contained in 65.0 mL of a 2.20 M solution of NaOH in H2O?

2 answers:

0 0

The number of moles of NaOh that are contained in 65ml of 2.20M solution NaOh in H2o is calculated using the below formula

moles = molarity x volume /1000

that is 65 x2.20 /1000= 0.143 moles

lakkis [162]4 years ago

0 0

Explanation:

Molarity is defined as number of moles divided by volume in liter.

Mathematically, Molarity = $\frac{no. of moles}{Volume in liter}$

Since, it is known that 1 L equals 1000 ml so 65.0 mL equals 0.065 L.

Therefore, it is given that volume is 0.065 L and molarity is 2.20 M. Hence, calculate number of moles as follows.

Molarity = $\frac{no. of moles}{Volume in liter}$

Number of moles = $Molarity \times Volume in liter$

= $2.20 M \times 0.065 L$

= 0.143 mol

Thus, we can conclude that there are 0.143 moles NaOH are contained in 65.0 mL of a 2.20 M solution of NaOH in $H_2O$ .

You might be interested in

1. How many molecules are in 4.5 moles?

Naily [24]

Answer:

2.4 ⋅ 10 24

Explanation:

All that you need to know here is that in order for a given sample of water to contain exactly 1 mole of water, it must contain 6.022 ⋅ 10 23 molecules of water.

This is known as Avogadro's constant and essentially acts as the definition of a mole. If you have 6.022 ⋅ 10 23 molecules of water, then you can say for a fact that you have 1 mole of water.

6 0

3 years ago

g What are the relative rates of diffusion of the three naturally occurring isotopes of krypton, 80Kr80Kr , 82Kr82Kr, and 83Kr83

emmasim [6.3K]

Solution :

According to the Graham's law of diffusion, we know that, the rate of the diffusion varies inversely to the molar mass of the gas, i.e.

Rate of diffusion, $r_d = \frac{a}{\sqrt M}$

where, the 'M' is the molar mass of the gas.

Now in the case of the isotopes of the Krypton,

Atomic mass of $^{80}Kr$ = 80 AMU

Atomic mass of $^{82}Kr$ = 82 AMU

Atomic mass of $^{83}Kr$ = 83 AMU

So the ratio of the rate of diffusion of the three isotopes are :

$M_{d,^{80}Kr}:M_{d,^{82}Kr}:M_{d,^{83}Kr}$

$=\frac{1}{\sqrt{80}}:\frac{1}{\sqrt{82}}:\frac{1}{\sqrt{83}}$

$=0.1118:0.1104:0.10976$

Dividing the above three with the smallest number among the three i.e. 0.10976, we get the relative rates of diffusion.

∴ $M_{d,^{80}Kr}:M_{d,^{82}Kr}:M_{d,^{83}Kr}$

= 1.02 : 1.01 : 1

Hence the relative rate of diffusion are :

$^{80}Kr(1.02)>^{82}Kr(1.01)>^{83}Kr(1.00)$

3 0

3 years ago

The dirigible Hindenburg had 3.7E6 m3 of hydrogen in its gas bags at 1.1 atm and 7°C. What was the weight of the hydrogen in pou

zepelin [54]

Assuming that the gas is ideal, we can use the ideal gas equation PV=nRT to calculate for the number of moles. Then, multiply the molar mass of the gas to obtain the mass. We do as follows:

PV = nRT
n = PV / RT
n = 1.1 atm (3.7x10^9 L) / 0.08205 L-atm/mol-K (280.15) = 177061931.3 mol H2

Mass = (177061931.3 mol H2) 18.02 g/mol ( 1 kg / 1000g) ( 2.2 lb / 1 kg ) = 7019443.21 lb H2

4 0

3 years ago

Which of the following atoms will form an ion with the most negative charge?

bekas [8.4K]

Answer:

hi i don't know the answer to this

3 0

3 years ago

Explain how the composition of magma affevt volcano eruptions?

larisa [96]

The kind of magma that is found in the most explosive volcanoes, the composite volcanoes, is andesitic magma. It is magma that is quite high in silica content which makes it thick, sticky and gooey. Great lumps of this sticky magma cool at the top of the volcano to form a sealed cap. Magma beneath the cap builds up and pressure mounts and eventually becomes too much to be contained and the magma violently erupts out from the top, blowing out the cap and shooting miles up into the air and in all directions.

The kind of magma found in gentle volcanoes such as shield volcanoes is runny in consistency. It has very minimal amounts of silica and is not thick but loose. It therefore tends to trickle out of the top of the volcano rather than erupt or explode.

8 0

3 years ago