Consider the following equilibrium:
4NH₃ (g) + 3O₂ (g) ⇄ 2N₂ (g) + 6H₂O (g) + 1531 kJ
The given statement is True, because
According to Le Ch's Principle:
Systems that have attained the state of chemical equilibrium will tend to maintain their equilibrium state.
External factors such as the addition of products and reactants result in the disruption of the equilibrium state.
we expect the system to shift to the direction that offsets the change in concentration.
This results in the state of chemical equilibrium to be reestablished.
Hence, The statement is true,
- The addition of more ammonia (a reactant) would offset the state of equilibrium.
- To restore chemical equilibrium, the system must consume the excess reactants to form more products.
- A shift to favor the products side occurs.
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1s^2 = filled
2s^2 = filled
2p^6 = filled
3s^1 = partially filled (need 2)
3 orbitals are completely filled.
Answer:
B. Ionic Compound
Explanation:
An ionic compound is that compound which contains a positively charged ion called CATION and a negatively charged ion called ANION. The cation loses or transfers electrons to the anion, hence, making the former (cation) positive and the latter (anion) negative.
A polyatomic ion is an ion that contains more than one type of atom e.g OH-, NO3²-, CO3²- etc. A polyatomic ion usually has an overall charge formed from the charges of the individual atoms that makes it up. For example, in OH-, the overall charge is -1.
Since a polyatomic ion can have an overall positive or negative charge, it must enter a reaction with another ion that complements it i.e. a negative polyatomic ion will react with a positive ion to neutralize its charge. Hence, this forms an IONIC COMPOUND. This is why most compounds with polyatomic ions are IONIC COMPOUNDS.
For example, CaCO3 is an ionic compound formed when Ca²+ (cation) reacts with the polyatomic anion: CO3²-
[CO] = 1 mol / 2L = 0.5 M
[
According to the equation:
and by using the ICE table:
CO(g) + H2O(g) ↔ CO2(g) + H2(g)
initial 0.5 0.5 0 0
change -X -X +X +X
Equ (0.5-X) (0.5-X) X X
when Kc = X^2 * (0.5-X)^2
by substitution:
1.845 = X^2 * (0.5-X)^2 by solving for X
∴X = 0.26
∴ [CO2] = X = 0.26