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Rina8888 [55]
3 years ago
8

Calculate the enthalpy change for the reaction 2 hcl → h2 + cl2 1. +184 kj/mol of rxn 2. +428 kj/mol of rxn 3. 0 kj/mol of rxn 4

. −184 kj/mol of rxn 5. −244 kj/mol of rxn
Chemistry
1 answer:
lesantik [10]3 years ago
5 0
Below is the list of enthalpies of formation of the compounds involved in the chemical reaction.

HCl: -92.3 kJ/mol
H2: 0 
Cl2: 0

Both H2 and Cl2 do not have enthaply of formation because they are pure substances. 

Since, in the reaction there are 2 moles of HCl,
   Enthalphy of formation = enthalpy of products - enthalphy of reactant/s
                = 0 - (-92.3)(2) = +184.6 kJ

Hence, the answer is the first choice. 
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The first law of thermodynamics is observed when
krek1111 [17]

Answer:

Explanation:

The first law of Thermodynamics is known as Conservation because it explains that energy is always maintained within a closed system and cannot be created or destroyed. Therefore, this is observed when there is no longer change in temperature in a system. Mainly because the energy is not being transferred to and from another system. Without this transfer of energy, the energy itself gets conserved within the system and the temperature no longer fluctuates.

8 0
3 years ago
Which element has this electron configuration? <br> astatine<br> bromine<br> chlorine<br> fluorine
oksano4ka [1.4K]
Unfortunately you did not specify the electronic configuration in the question, however since one of the answers must be a halogen, i took the liberty to attach an image with the configuration (both the simple numeric and spdf form) for all the halogen and all you have to do is match the electronic configuration you have in your question to the one in the table attached and you can then deduce the answer.

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7 0
3 years ago
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Makovka662 [10]

Answer:

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8 0
3 years ago
Complete and balance the following redox reaction in basic solution
inn [45]

Answer:

balanced in ACID not BASE

Cr2O7^2-(aq) +3Hg(l) +14 H^1+ ----> 3Hg^2+ + 2Cr^3+(aq) + 7H2O

Answer

Cr2O7^2-(aq) +3Hg(l) +14 H^1+ ----> 3Hg^2+ + 2Cr^3+(aq) + 7H2O

Explanation:

Cr2O7^2-(aq) + Hg(l) ----> Hg^2+(aqH) + Cr^3+(aq)

add H^1+ (acid) to capture the O and make 7 water molecules

Cr2O7^2-(aq) + Hg(l) + H^1+ ----> Hg^2+(aqH) + Cr^3+(aq) + 7H2O

Cr goes from +6 to +3 by gaining 3 e

Hg goes from 0 to +2 by losing 2 e

we need 3 Hg for every 2 Cr

so

Cr2O7^2-(aq) +3Hg(l) +14 H^1+ ----> 3Hg^2+ + 2Cr^3+(aq) + 7H2O

2 Cr on the right and left

Net 12 positive charges on the right and the left

3 Hg on the right and left

14 H on the right and left

the equation is balanced

we cannot balance the equation in a basic solution with OH^1-

we have plenty of O in the dichromate ion. we need to convert it to water which take free H^1+ from the acid

8 0
3 years ago
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Strike441 [17]

Answer:

19.4 g of alum, will be its theoretical yield

Explanation:

The reaction is:

2 Al + 2 KOH + 4 H₂SO₄ + 22H₂O → 3H₂ + 2KAl(SO₄)₂•12H₂O

Let's determine the amount of acid.

M are the moles contained in 1 L of solution or it can be mmoles that are contained in 1 mL of solution

M = mmol /mL

M . mL = mmol

We replace: 8.3 mL . 9.9 M = 82.17 mmoles

We convert to moles: 82.17 mmol . 1 mol / 1000mmol = 0.082 moles

Ratio is 4:2

4 moles of sulfuric acid can make 2 moles of alum

By the way, 0.082 moles of acid may produce ( 0.082 . 2) /4 = 0.041085 moles.

We convert moles to mass:

Molar mass of alum is: 473.52 g/mol.

0.041085 moles . 473.52 g/mol = 19.4 g

6 0
3 years ago
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