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valentinak56 [21]

2 years ago

7

A 2.4 m long rod of mass m1 = 14 kg, is supported on a knife edge at its midpoint. A ball of clay of mass m2 = 3.5 kg is dropped

from rest from a height of h = 1.4 m and makes a perfectly inelastic collision with the rod 0.9 m from the point of support. Find the angular momentum of the rod and clay system about the point of support immediately after the inelastic collision.

1 answer:

Mashutka [201]2 years ago

7 0

Explanation:

It is known that;

$L_{i} = L_{f}$

Now, we need to calculate the value of L, that is, angular momentum.

Therefore,

L= mvr

where, m = mass

v = velocity

r = radius

Hence,

L = $m(\sqrt{2gh}) \times r$

So,

L = $(2.2 \times (\sqrt{2 \times 9.81 \times 1.4}) \times 0.9)$

= 10.37 Js

Thus, we can conclude that angular momentum of the rod and clay system about the point of support immediately after the inelastic collision is 10.37 Js.

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