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2 years ago

12

At this rate, how long would it take for two continents 2900 km kilometers apart to collide?

1 answer:

Sophie [7]2 years ago

3 0

At what rate??????????

You might be interested in

When an object moves, stops moving, changes speed, or changes direction, how do scientists describe that condition?

lorasvet [3.4K]

Drop "moves" from the list for a moment.

You can also drop "stops moving", because that's included in "changes speed"
(from something to zero).

When an object changes speed or changes direction, that's called "acceleration".

I dropped the first one from the list, because an object can be moving,
and as long as it's speed is constant and it's moving in a straight line,
there's no acceleration.

I think you meant to say "starts moving". That's a change of speed (from zero
to something), so it's also acceleration.

8 0

2 years ago

An aluminum wire is 5.87 m long and has a diameter of 6.07 mm.

antoniya [11.8K]

Answer: 5.72 x 10-3Ω

Explanation:

Hi, to answer this question, first we have to calculate the cross sectional area of the cable:

Diameter (D)=6.07 mm

Since: 1000mm = 1m

6.07mm/ 1000mm/m = 0.00607 meters

Area of a circle : π (d/2)^2

A = π (0.00607/2)^2= 0.000028937 m2

Resistance formula:

Resistance (R) = P(resistivity) L (length)÷A (cross sectional area )

Replacing with the values given:

R = (2.82x10-8 x 5.87) / 0.000028937

R = 5.72 x 10-3Ω

Feel free to ask for more if needed or if you did not understand something.

7 0

2 years ago

A charged cloud system produces an electric field in the air near earth's surface. a particle of charge -2.0 × 10-9 c is acted o

defon

Part a)

Magnitude of electric field is given by force per unit charge

$E = \frac{F}{q}$

$E = \frac{4.3 * 10^{-6}}{2 * 10^{-9}}$

$E = 2150 N/C$

Part b)

Electrostatic force on the proton is given as

F = qE

$F = 1.6 * 10^{-19} * 2150$

$F = 3.44 * 10^{-16} N$

PART C)

Gravitational force is given by

$F_g = mg$

$F_g = 1.6 * 10^{-27}*9.8$

$F_g = 1.57 * 10^{-26} N$

PART d)

Ratio of electric force to weight

$\frac{F_e}{F_g} = \frac{3.44 * 10^{-16}}{1.57*10^{-26}}$

$\frac{F_e}{F_g} = 2.2 * 10^{10}$

7 0

2 years ago

Suppose you first walk 12.0 m in a direction 200 west of north and then 20.0 m in a direction 40.00 south of west. How far are y

Tpy6a [65]

Complete Question

The complete question is shown on the first uploaded image

Answer:

the compass direction of the resultant displacement is $\theta =4.7^o$ south of west

Explanation:

Generally using cosine we can obtain the resultant R as follows

$R^2 = A^2 + B^2 -2ABcos(70)$

=> $R = \sqrt{12^2 + 20^2 - 2(12 ) * (20) cos 70}$

=> $R = 19.48 \ m$

We can obtain the direction of the resultant by first using sine rule to obtain angle C as follows

$\frac{A}{sin C} = \frac{R}{sin70 }$

=> $C= sin ^{-1} [\frac{A * (sin 70)}{R} ]$

=> $C = sin ^{-1} [\frac{20 * (sin 70)}{19.48} ]$

=> $C = 74.7 ^o$

Then the direction is obtained as

$\theta = C - 70$

=> $\theta = 74.7 - 70$

=> $\theta =4.7^o$

Hence the compass direction of the resultant displacement is $\theta =4.7^o$ south of west

7 0

2 years ago

In which direction would the circle go if it was in between a positive and negative charge

evablogger [386]

It would go to the positive charge im like 99% sure of that

7 0

2 years ago