Answer: Distance is the actual position traveled by an object. Displacement is the shortest distance covered by the object.
Explanation:
Distance is the actual length covered by an object from one position to another. It is a scalar quantity. It cannot be negative.
Displacement is the shortest distance covered by the object. The displacement can be calculated by subtracting initial distance from the final distance. It is vector quantity. The displacement covered by an object can be zero, negative and positive.
Suppose, the boy travels from home to school then come back to his home. The distance between from his home to his school is 3 km.
In this case, the boy covers the total distance from home to school then to home is 6 km. But the displacement is zero because he comes to same position.
Answer:
Moment of Force, M = 51.6 lbf-ft
Explanation:
Given,
The fishing rod AB of length, L = 6 ft
The force acting on the rod, F = 8.6 lbf
The moment of force about A is given as the product of force and perpendicular distance. It is given by the formula
M = F x L
Substituting the given values in the above equation
M = 8.6 lbf x 6 ft
= 51.6 lbf-ft
The moment about A of the force exerted by the line at B is, M = 51.6 lbf-ft
a) Gravitational force only
b) Normal force only
c) Gravitational force, normal force, and frictional force
d) Gravitational force and normal force
Answer:
Answer below!!
Explanation:
Every observer would observe the same image location and every light ray would follow the law of reflection.Yet only two of these rays would be needed to determine the image location since it only requires two rays to find the intersection point.
Hope I helped!!
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Answer:
change in gravitational potential energy Δ PE = 392 J
Explanation:
given data
mass of the person m = 80 kg
height of the centre of mass Δh = 0.50 m
to find out
change in gravitational potential energy
solution
we get here change in gravitational potential energy that is express here as
change in gravitational potential energy Δ PE = m × g × Δh .........1
put here value we get
change in gravitational potential energy Δ PE = m × g × Δh
change in gravitational potential energy Δ PE = 80 × 9.8 × 0.50
change in gravitational potential energy Δ PE = 392 J