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Alinara [238K]
3 years ago
7

What is a force on the object if it has a mass of 10.41 kg and an acceleration of 6.5 m/s2

Physics
1 answer:
Fudgin [204]3 years ago
4 0
To determine the force of the system, we use Newton's Second Law of motion which relates force and mass where they are directly proportional and the constant of proportionality is the acceleration. We calculate as follows:

F = ma
F = 10.41 kg ( 6.5 m/s^2 )
F = 67.67 kg m / s^2 or N
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A sealed tank containing seawater to a height of 12.8 m also contains air above the water at a gauge pressure of 2.90 atm . Wate
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Answer:

The velocity of water at the bottom, v_{b} = 28.63 m/s

Given:

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Now,

Atmospheric pressue, P_{atm} = 1 atm = 1.01\tiems 10^{5} Pa

At the top, the absolute pressure, P_{t} = P_{gauge} + P_{atm} = 2.90 + 1 = 3.90 atm = 3.94\times 10^{5} Pa

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The velocity at the top, v_{top} = 0 m/s, l;et the bottom velocity, be v_{b}.

Now, by Bernoulli's eqn:

P_{t} + \frac{1}{2}\rho v_{t}^{2} + \rho g h_{t} = P_{b} + \frac{1}{2}\rho v_{b}^{2} + \rho g h_{b}

where

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\sqrt{\frac{2(P_{t} - P_{b} + \rho g(h_{t} - h_{b}))}{\rho}} =  v_{b}

\sqrt{\frac{2(3.94\times 10^{5} - 1.01\times 10^{5} + 1030\times 9.8\times 12.8}{1030}} =  v_{b}

v_{b} = 28.63 m/s

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