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3 years ago

What is a force on the object if it has a mass of 10.41 kg and an acceleration of 6.5 m/s2

1 answer:

4 0

To determine the force of the system, we use Newton's Second Law of motion which relates force and mass where they are directly proportional and the constant of proportionality is the acceleration. We calculate as follows:

F = ma
F = 10.41 kg ( 6.5 m/s^2 )
F = 67.67 kg m / s^2 or N

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A 40-W lightbulb is 1.7 m from a screen. What is the intensity of light incident on the screen? Assume that a lightbulb emits ra

Sonja [21]

Answer:

Intensity, $I=1.101\ W/m^2$

Explanation:

Power of the light bulb, P = 40 W

Distance from screen, r = 1.7 m

Let I is the intensity of light incident on the screen. The power acting per unit area is called the intensity of the light. Its formula is given by :

$I=\dfrac{P}{A}$

$I=\dfrac{P}{4\pi r^2}$

$I=\dfrac{40\ W}{4\pi (1.7\ m)^2}$

$I=1.101\ W/m^2$

So, the intensity of light is $1.101\ W/m^2$ .

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4 years ago

How does pressure affect surface tension

tatyana61 [14]

the effect of pressure on surface tension can be attributed in part to absorption of gas at the surface of the liquid and in part to an intrinsic decrease in density of the liquid in the neighborhood of the surface.

In the case of liquids , Owing to contact forces between the edge of the surface and the vessel, the surface acquires a curvature, and if the liquid rises up at the edges where it meets the vessel, the pressure will be less in the liquid than in the air, for points just below and just above the surface. The vessel exerts an upward force on the liquid. This is simply a matter of looking at the directions of forces acting, knowing that the surface is under tension.

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3 years ago

A horizontal uniform bar of mass 2.7 kg and length 3.0 m is hung horizontally on two vertical strings. String 1 is attached to t

Jlenok [28]

Answer:

14.36 N

Explanation:

$T_{1}$ = Tension in string 1

$T_{2}$ = Tension in string 2

$m_b$ = mass of the bar = 2.7 kg

$W_b$ = weight of the bar

weight of the bar is given as

$W_b = m_{b} g = (2.7) (9.8) = 26.46$ N

$m_m$ = mass of the bar = 1.35 kg

$W_m$ = weight of the monkey

weight of the monkey is given as

$W_m = m_{m} g = (1.35) (9.8) = 13.23$ N

Using equilibrium of torque about left end

$W_{m} (AB) + W_{b} (AB) = T_{2} (AC)\\W_{m} (AB) + W_{b} (AB) = T_{2} (AD - CD)\\(13.23) (1.5) + (26.46)(1.5) = T_{2} (3 - 0.65)\\\\T_{2} = 25.33$ N

Using equilibrium of force in vertical direction

$T_{1} + T_{2} = W_{b} + W_{m}\\T_{1} + 25.33 = 26.46 + 13.23\\T_{1} = 14.36$ N

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3 years ago

lan wrote the following phrase to describe the movement of particles in a state of matter. "Spheres jiggle together in a locked

Vladimir [108]

Most likely solid. Molecules move in a chaotic matter, which a Scottish botanist found out in the 19th century. In gases, this chaotic movement is the most “dramatic” and they move around freely; in liquids it’s a bit less noticeable, and in solids the particles oscillate around locked positions. Movement in plasma is similar to gas.

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3 years ago

Read 2 more answers

How much energy does the electron have initially in the n=4 excited state?what is the change in energy if the electron from part

Ierofanga [76]

What it looks to be that you found in A was the "initial"...b/c the question asks:
"how much energy does the electron have 'initially' in the n=4 excited state?" 

"final" would be where it 'finally' ends up at, ie. its last stop...as for this question...the 'ground state' as in its lowest energy level. 

The answer comes to: −1.36×10^−19 J

You use the same equation for the second part as for part a.
just have to subract the 2 as in the only diff for part 2 is that you use 1squared rather than 4squared & subract "final -initial" & you should get -2.05*10^-18 as your answer.

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3 years ago