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sineoko [7]
2 years ago
10

Which characteristics best identify differences between intrusive and extrusive

Chemistry
1 answer:
tresset_1 [31]2 years ago
8 0
Intrusive -inside
extrusive -outside
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Sodium bromide equation
asambeis [7]
The equation would be NaBr
7 0
2 years ago
Write the structure of the following compound:<br>=&gt; 3-(4-chlorophenyl)-2-methylpropane
Rudiy27

Answer:

See explanation and image attached

Explanation:

The IUPAC system of nomenclature enables the structure of molecules to be written seamlessly from the name of the compound. Hence it is commonly called the systematic nomenclature.

The parent chain here is propane. It is substituted at the 2- position by a methyl group and at the 3-position by 4-chlorophenyl group as we can see in the image attached to this answer.

7 0
3 years ago
What are the two fundamental portions of an atom?​
Mice21 [21]
Number of Protons in an Uncharged Atom
The two main components of an atom are the nucleus and the cloud of electrons. The nucleus contains positively charged and neutral subatomic particles, whereas the cloud of electrons contains tiny negatively charged particles.
4 0
3 years ago
Which shows the rational expression written using the least common denominator?
Alexandra [31]

Answer:

The first one.

\frac{x + 1}{4x^{2} } and \frac{4(x + 1)}{4x^{2} }

Explanation:

When comparing two fractions with variables like this, it's important to get to the same denominator in order to compare apples with apples and then be able to do not only comparisons but also perform additions/subtractions.

Question is which denominator to use and how to reach it.

In this case, the question and the answer choices do the work for you.  The question asks which one is the LEAST common denominator, and the answers show denominators x² and 4x².  The smallest of these is x², however, we can't simplify the first fraction to get to the x² denominator, so we'll go for the 4x².

So, the first fraction has already the correct denominator (4x²), we just have to transform the second one.

We multiply it by 1, expressed in a different way.  Since we're multiplying by one, we're not affecting the value, just the way it looks.

Let's do it!, to get the denominator to go from x² to 4x², we need to multiply it by 4... so we'll multiply by 4/4 (which is 1, neutral for the multiplication).

\frac{x + 1}{x^{2} } * \frac{4}{4} = \frac{4(x + 1)}{4x^{2} }

And now you have both fractions on the same denominator, without having changed their value, just their looks

6 0
3 years ago
3 Na2O(aq) + 2 Al(NO3)3(aq) ----&gt; _ Compound A + _ Compound B
Olin [163]
3Na2O(at) + 2Al(NO3)3(aq) —> 6NaNO3(aq) + Al2O3(s)

This is a double replacement reaction and NaNO3 is aqueous because Na is an alkali metal, plus nitrate is in the solution. Both of these are soluble. Al2O3 is not soluble because it does not contain any element that is soluble and is hence the precipitate.

Hope this helped!
7 0
3 years ago
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