Answer:
1.1 × 10² g
Explanation:
The combustion of gasoline releases energy that is used to move the car. The enthalpy of reaction (ΔH°rxn) of the combustion of gasoline is 47 kJ/g, that is, 47 kiloJoule are produced per gram of gasoline burned. The mass of gasoline to be burned to release 5,375 kJ is:
5,375 kJ × 1 g Gasoline/47 kJ = 1.1 × 10² g
Molar mass of methanol=12 + 1×3 + 16 + 1=32g
<span>
</span>
Im not really sure but my best guess is d 52.8%
Answer:
+3
Explanation:
The oxygen all have a -2 oxidation state. (peroxides are exceptions)
The chemical structure is symmetrical. Both carbon are equivalent.
2 (oxidation state of carbon) + 4 (oxidation state of oxygen) = charge of ion.
2 (oxidation state of carbon) + 4 (-2) = -2
oxidation state of carbon = +3
Answer: 31.55 g
Explanation:
- The mass number of Fluoride atom (F) = 18.99 g/mol, so mass number of fluorine gas (F2) = 37.98 g/mol.
- 1 mole of (F2) [which has 37.98 g/mol] contains Avogadro’s number of molecules (6.02×10^23 molecules),
so 1 mole of (F2) with 37.98 g/mol → 6.02×10^23 molecules.
- Using cross multiplication,
37.98 g/mol of (F2) → 6.02 ×10^23 molecules
? → 5.00 ×10^23 molecules
Hence the mass of 5.00×10^23 molecules of F2 = (37.98 × 5.00 × 10^23) / 6.02 ×10^23 = 31.55 g..
