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Ilya [14]
3 years ago
7

Calculate the percent by mass of carbon in CO2 (carbon dioxide). Please show all work.

Chemistry
1 answer:
anygoal [31]3 years ago
6 0
%C= 12/12 + 2·16=0,273=27,3%.
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Using the equation, C5H12 + 8O2 Imported Asset 5CO2 + 6H2O, if 2 moles of pentane (C5H12) were supplied, and an unlimited amount
Kamila [148]

12 moles of water H₂O are produced from the combustion of pentane.

Explanation:

We have the following combustion of pentane (C₅H₁₂):

C₅H₁₂ + 8 O₂ → 5 CO₂ + 6 H₂O

Knowing the chemical reaction we devise the following reasoning:

if         1 moles of pentane C₅H₁₂ produces 6 moles of water H₂O

then    2 moles of pentane C₅H₁₂ produces X moles of water H₂O

X = (2 × 6) / 1 = 12 moles of water H₂O

Learn more about:

combustion of organic compounds

brainly.com/question/7295137

brainly.com/question/884053

#learnwithBrainly

7 0
3 years ago
A chemist titrates 130.0mL of a 0.4248 M lidocaine (C14H21NONH) solution with 0.4429 M HBr solution at 25 degree C . Calculate t
jeka57 [31]

Answer:

pH = 3.36

Explanation:

Lidocaine is a weak base to be titrated with the strong acid HBr, therefore at equivalence point we wil have the protonated lidocaine weak conjugate acid of lidocaine which will drive the pH.

Thus to solve the question we will need to calculate the concentration of this weak acid at equivalence point.

Molarity = mol /V ∴ mol = V x M

mol lidocaine = (130 mL/1000 mL/L) x 0.4248 mol/L = 0.0552 mol

The volume of 0.4429 M HBr required to neutralize this 0.0552 mol is

0.0552 mol x  (1L / 0.4429mol) = 0.125 L

Total volume at equivalence is  initial volume lidocaine + volume HBr added

0 .130 L +0.125 L = 0.255L

and the concentration of protonated lidocaine at the end of the titration will be

0.0552 mol / 0.255 L = 0.22M

Now to calculate the pH we setup our customary ICE table for  weak acids for the equilibria:

protonated lidocaine + H₂O   ⇆  lidocaine + H₃O⁺

                      protonated lidocaine          lidocaine        H₃O⁺

Initial(M)               0.22                                       0                  0

Change                   -x                                      +x                 +x

Equilibrium          0.22 - x                                  x                    x

We know for this equilibrium

Ka = [Lidocaine] [H₃O⁺] / [protonaded Lidocaine] =  x² / ( 0.22 - x )

The Ka can be calculated from the given pKb for lidocaine

Kb = antilog( - 7.94 ) = 1.15 x 10⁻⁸

Ka = Kw / Kb = 10⁻¹⁴ / 1.15 x 10⁻⁸  = 8.71 x 10⁻⁷

Since Ka is very small we can make the approximation 0.22  - x  ≈ 0.22

and solve for x. The pH  will then  be the negative log of this value.

8.71 x 10⁻⁷  = x² / 0.22 ⇒ x = √(/ 8.71 X 10⁻⁷ x 0.22) = 4.38 x 10⁻⁴

( Indeed our approximation checks since 4.38 x 10⁻⁴ is just 0.2 % of 0.22 )

pH = - log ( 4.4x 10⁻⁴) = 3.36

3 0
3 years ago
How many moles of H2O form when 4.5 moles O2 reacts?
mart [117]

Explanation:

Start with a balanced equation.

2H2 + O2 → 2H2O

Assuming that H2 is in excess, multiply the given moles H2O by the mole ratio between O2 and H2O in the balanced equation so that moles H2O cancel.

5 mol H2O × (1 mol O2/2 mol H2O) = 2.5 mol O2

Answer: 2.5 mol O2 are needed to make 5 mol H2O, assuming H2 is in excess.

4 0
3 years ago
Which of earths spheres contains most of its mass?
zysi [14]
The geosphere is about 99.94% of Earth's mass, so C is the answer.
8 0
3 years ago
Read 2 more answers
Based on the greenhouse effect, if the amount of carbon dioxide in the air decreased, what would happen?
choli [55]
A) the average global temp. Would decrease
7 0
3 years ago
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