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3 years ago

What missions have been sent to explore Venus and what did they discover

Physics

2 answers:

faust18 [17]3 years ago

6 0

Answer:

See below

Explanation:

Venus Express (2005 - 14)
Galileo (1989 - 90): As it flew by Venus on its way to Jupiter, it collected measurements of charged particles, dust and magnetism, infrared and ultraviolet spectral observation, data for infrared lower - atmosphere maps, and 81 camera images
Magellan (1989 - 90)
Vega 1 (1984 - 85)
Vega 2 (1984 - 85)
Venera 4 (1964): Atmosphere made up of entirely carbon dioxide, found that temperatures ranged from 40 degrees Celsius high up in the atmosphere to 280 degrees Celsius closer to the surface, and pressures ranged 15 to 22 atmospheres
Venera 6 (1969)
Venera 7 (1970): Became first spacecraft to return data from another planet and reported surface temperature of 475 degrees Celsius and atmospheric pressure 90 times greater than Earth's
Venera 8 (1972)
Venera 9 (1975)
Venera 10 (1975): Transmitted images from the surface
Venera 11 (1978): Sent back evidence of thunder and lightning as well as presence of carbon monoxide in lower altitude
Venera 12 (1978)
Venera 13 (1981 - 82): Returned first color images and found out the pressure was 84 times the pressure at sea level on Earth and the temperature was 457 degrees Celsius, before succumbing to them
Venera 14 (1981 - 82): Sent back images of Venus
Venera 15 (1983): Created radar map of Venus with Venera 16
Venera 16 (1983)
Pioneer Venus 1 (1978): Radar mapped nearly the entire planet, resolving features as small as 80 kilometers
Pioneer Venus 2 (1978): Consisted of 4 separate atmospheric probes
Mariner 2 (1962): Flyby attempt discovered ground temperatures as high as 428 degrees Celsius, but detected no water vapor or evidence of a magnetic field around planet
Mariner 5 (1967): During flyby, measured surface temperature of 267 degrees Celsius
Mariner 10 (1973 - 74): Took first ultraviolet images of Venus on way to Mercury
Akatsuki/Venus Climate Orbiter (2010 - today)

These are just some of the successful attempts by probes at or near Venus.

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ladessa [460]3 years ago

4 0

Answer:

Explanation:

The other answer misses the most recent Venus mission: the Parker Solar Probe. It was launched by NASA in 2018 for observing the Sun. On its way there, the probe is doing several fly-bys to Venus; using the planet for gravity assist propelling it to the Sun.

Because its primary mission is to investigate the Sun, the Parker Solar Probe does not have a lot of researches planned for Venus.

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Find its moment of inertia about an axis perpendicular to its plane and passing through the midpoint of the line connecting its

antoniya [11.8K]

A) Moment of inertia about an axis passing through the point where the two segments meet : $I_A=\frac{1}{12} M L^2$

B) Moment of inertia passing through the point where the midpoint of the line connects to its two ends: $I x=\frac{1}{3} M L^2$

What is Moment of inertia?

The term "moment of inertia" refers to a physical quantity that quantifies a body's resistance to having its speed of rotation along an axis changed by the application of a torque (turning force). The axis might be internal or exterior, fixed or not.

A) The moment of inertia about an axis passing through the point where the two segments meet is $I_A=\frac{1}{12} M L^2$ given that the rod is bent at the center and distance from all the points to the axis remains the same, the moment of inertia about the center will remain the same.

B) Determine the moment of inertia about an axis passing through the point midpoint of the line which connects the two ends

First step: determine the distance between the ends ( d )

After applying Pythagoras theorem $\mathrm{d}=\frac{\sqrt{2}}{2} L$

Next step : determine distance between the two axis $(\mathrm{x})$

After applying Pythagoras theorem

$\mathrm{x}=\frac{\sqrt{2}}{4} L$$$

Final step : Calculate the value of $\mathrm{I}_{\mathrm{x}}$

applying Parallel Axis Theorem

$I_x=I_8+M x^2$

$\begin{aligned}& =\frac{1}{12} M L^2+\frac{1}{4} M L^2 \\& \therefore \quad I x=\frac{1}{3} M L^2 \\&\end{aligned}$

Hence we can conclude that Moment of inertia about an axis passing through the point where the two segments meet: $I_A=\frac{1}{12} M L^2$ , Moment of inertia passing through the point where the midpoint of the line connects its two ends: $I x=\frac{1}{3} M L^2$

To learn more about moment of inertia visit:brainly.com/question/15246709

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5 0

1 year ago

A 15 kg kangaroo jumps with an upward acceleration of 3 m/s2 by pushing hard off the ground.

patriot [66]

Explanation:

The net force would be upwards since the kangaroo would have to overcome gravity to jump

3 0

3 years ago

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falling objects drop with an average acceleration of 9.8m/sec/sec. if an object falls from a tall building how long will it take

sveta [45]

Answer:

5 seconds

Explanation:

Acceleration = (final velocity - initial velocity) ÷ time

$a = \frac{v - u}{t}$

$9.8 = \frac{49 - 0}{t}$

$9.8 = \frac{49}{t}$

$9.8t = 49$

$t = \frac{49}{9.8}$

$t = 5$

8 0

3 years ago

Which is the one factor that adds to the greenhouse effect? 1. a decrease in the amount of dust in the atmosphere 2. a decrease

lukranit [14]

Answer:

an increase in gasses that absorb heat

Explanation:

Greenhouse effect refers to the gradual increase in the earth's temperature due to an increase in the concentration of certain gases in the atmosphere. These gases are called greenhouse gases and they include; water vapour, nitrogen 1 oxide, carbon IV oxide etc. Green house effect is said to occur when heat radiating outwards from the earth surface towards space is trapped close to the earth's surface due to the presence of greenhouse gases in the atmosphere.

Greenhouse effect leads to increase in the temperature of the earth, melting of polar ice caps and possibly flooding due to a rise in sea levels.

Greenhouse gases act as glass in a greenhouse. They allow heat to pass through onto the earth surface but trap the heat and prevent it from being radiated outwards back to space. Thereby increasing the surface temperature of the earth.

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3 years ago

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What is the magnification of a real image if the image is 15.0 cm from a lens and the object is 60.0 cm from the lens?

Hoochie [10]

Answer:

soluble

Explanation:

7 0

2 years ago

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