HMU IM BOARD
2 answers:
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Answer:
The molecular weight is 77.7 kg/mol
Explanation:
The molecular mass of hemoglobin is equal to:
Where
R = molar gas constant = 8.315 J/K mol
p = density = 0.998 g/mL
V = specific volume = 0.755 mL/g
s = sedimentation rate = ?
D = diffusion rate = 7x10⁻¹¹m²/s
T = temperature = 303 K
The sedimentation rate is equal to:
Where
w = angular velocity = 39300 rpm = 246929.18 rad/min
xb,30 = boundary midpoint distance at 30 min = 4.525 + 0.074 cm
t = time = 30 min
xb,0 = boundary midpoint distante at 0 min = 4.525 cm
The molecular weight is:
Your question is incomplete. However, I found a similar problem fromanother website as shown in the attached picture.
To solve this problem, you must know that at STP, the volume for any gas is 22.4 L/mol. So,
Moles O₂: 156.8 mL * 1 L/1000 mL* 1 mol/22.4 L = 0.007 moles
Mass calcium: 0.007 mol O₂ * 2 mol Ca/1 mol O₂ * 40 g/mol Ca =<em> 0.56 g Ca</em>
To solve this problem, you must know that at STP, the volume for any gas is 22.4 L/mol. So,
Moles O₂: 156.8 mL * 1 L/1000 mL* 1 mol/22.4 L = 0.007 moles
Mass calcium: 0.007 mol O₂ * 2 mol Ca/1 mol O₂ * 40 g/mol Ca =<em> 0.56 g Ca</em>