Answer:
The speed of the boxes are 1 m/s.
Explanation:
Given that,
Mass of box = 1 kg
Mass of another box = 2 kg
Suppose 1 kg box moves with 3 m/s speed.
We need to calculate the speed of the boxes
Using formula of conservation of momentum
Where, u = initial velocity
v = final velocity
Put the value into the formula
Hence, The speed of the boxes are 1 m/s.
Answer:
g'(10) =
Explanation:
Since g is the inverse of f ,
We can write
g(f(x)) = x <em> </em><em>(Identity)</em>
Differentiating both sides of the equation we get,
g'(f(x)).f'(x) = 1
g'(10) = --equation[1] Where f(x) = 10
Now, we have to find x when f(x) = 10
Thus 10 = + 2
= 8
x =
Since f(x) = + 2
f'(x) = -
f'() = -4 × 4 = -16
Putting it in equation 1, we get:
We get g'(10) = -
Answer:
See solution with all the conditions considered. A gaseous mixture of A and B for which species A is chemically consumed at the catalytic surface.
The total pore reaction rate is stated below and it can be inferred by applying the bellow analogy.
