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BartSMP [9]
3 years ago
10

Weak tea is an example of a...

Chemistry
1 answer:
podryga [215]3 years ago
3 0
It is a dilute solution

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What is the symbol for the isotope of 58co that possesses 33 neutrons?
Cerrena [4.2K]

Cobalt because it has an atomic mass of 58 and 33 neutrons.

3 0
3 years ago
The half life of tritium is 12.3 years. How much sample will remain if you start with 425g of tritium that is found after 4 half
natta225 [31]

Answer:

26.56g

Explanation:

The half life of an isotope decay is the time transcurred when the initial amount of the isotope decays to the half of its amount.

For the problem, when 1 half life transcur, the sample has a mass of:

425g / 2 = 212.5g

When 2 half lives transcur:

212.5g / 2 = 106.25g

3 half lives:

106.25/2 = 53.13g

And the amount that is found after 4 half lives is:

53.13/2 =

<h3>26.56g</h3>
3 0
3 years ago
Kate’s blood volume is 3.8L. Before treatment,if her blood glucose was 170 mg/dL, how many grams of glucose were in her blood?
LiRa [457]

Answer:

6.460 gm  is the correct answer .

Explanation:

Given

Kate’s blood volume=3.8L

blood glucose=170\  mg/dL

As we know that

1\ dL= 10^{-1}\ litre

The 10^{-1}   includes the blood glucose of the 170\  mg/dL,

So 3.8L. of the Kate’s blood volume  can be determined by

=\ \frac{170 * 3.8 }{10^{-1} }

=170 * 38 \ mg

=6460\ mg

To convert into the gm we have divided by the 1000

6.460 \ gm

Therefore the glucose in her blood=

6.460 \ gm

3 0
3 years ago
Read 2 more answers
Calculate the number of molecules in 6.7 moles of AlCl3
Greeley [361]

According to the Avogadro’s law I mole of any substance contains = 6.023 x 1023

Number of molecules in one mole= 6.023 x 1023

Therefore number of molecules in 6.7 moles of AlCl3:

6.023x1023 molecules /1.0 mole * 6.7 mole

= 40.3541 x 1023 molecules

= 4.03541 x 1024 molecules


3 0
4 years ago
Help asap for Brainlist
White raven [17]

Answer:

3rd option

Explanation:

6 0
3 years ago
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