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Lynna [10]
3 years ago
14

A 14,000-kg boxcar is coasting at 1.50 m/s along a horizontal track when it suddenly hits and couples with a stationary 10,000-k

g boxcar. What is the speed of the cars just after the collision?
Physics
1 answer:
ludmilkaskok [199]3 years ago
5 0

Explanation:

It is given that,

Mass of a box car, m_1=14000\ kg

Initial speed of a box car, u_1=1.5\ m/s

Initial speed of another stationary car is 0 as it was stationary

Mass of another box car is 10,000 kg

Let V is the speed of the cars just after the collision. It is based on the concept of inelastic collision. So, using the conservation of linear momentum we get :

m_1u_1+m_2u_2=(m_1+m_2)V\\\\m_1u_1=(m_1+m_2)V\\\\V=\dfrac{m_1u_1}{(m_1+m_2)}\\\\V=\dfrac{14000\times 1.5}{(14000+10000)}\\\\V=0.875\ m/s

So, the speed of the cars just after the collision is 0.875 m/s.

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BlackZzzverrR [31]

<u>Answer:</u>

The correct answer option is D.  The distance between the planet and the Sun changes as the planet orbits the sun.

<u>Explanation:</u>

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According to the Kepler's first law of planetary motion: the path on which the planets orbit around the sun is elliptical in shape, with the center of the sun at one focus.

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6 0
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How do you find the average speed of an object?
Aleonysh [2.5K]

Answer:

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Answer:

v = 14 m/s

Explanation:

given,

radius of dip = 40 m

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A =\dfrac{3W}{2}

A =\dfrac{3mg}{2}

When the car is at the bottom,  the weight will be acting downwards and the centripetal force will also be acting downward where as Normal force which is apparent weight will be acting in upward direction.

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v = \sqrt{\dfrac{rg}{2}}

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