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Ymorist [56]
3 years ago
12

Gravity pulls gases and dust particles in space toward one another, squeezing them into a smaller and smaller space. The tempera

ture at the center rises high enough for fusion of hydrogen to begin. What stage in a stars life cycle is this describing?
A. The birth of a star.
B. The death of a star.
C. Black Hole.
D. Stellar Nebula.
Physics
1 answer:
Lady bird [3.3K]3 years ago
7 0
B. The Death of a star
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What is the physical representation of the area under a force versus extension or compression curve?
lidiya [134]

The compression curve would be theoretically given for a system of bodies in which the spring applies the force (Although in the same way the following process can be extrapolated to any system, depending on the type of Force to consider) For a spring mass system, the strength is given by Hooke's law as

F = Kx

Where,

K  = Spring constant

x = Displacement

If we integrate based on distance we would have

\int F = \int K x dx

This integral represents the area under the Force Curve based on each distance segment traveled.

\int F = K \int xdx

\int F = K (\frac{1}{2} x^2)

\int F = \frac{1}{2} Kx^2

This is the same formula that represents the elastic potential energy of a body. Therefore the correct answer is D.

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4 years ago
Devonte pushes a wheelbarrow with 830 W of power. How much work is required to get the wheelbarrow across the yard in 11 s? Roun
zaharov [31]
9,100 is the answer if you do the work so i failed for yall you welcome
8 0
3 years ago
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How does a plane and parachute manipulate air resistance differently?
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A planes wings are slightly tilted catching the air as it passes, keeping it afloat
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3 0
3 years ago
What is the direction and speed of an object?
KatRina [158]

Answer:

Explanation:

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7 0
4 years ago
Part b suppose the magnitude of the gravitational force between two spherical objects is 2000 n when they are 100 km apart. what
kobusy [5.1K]
<span>b) The force with a distance of 150 km is 889 N c) The force with a distance of 50 km is 8000 N This question looks like a mixture of a question and a critique of a previous answer. I'll attempt to address the original question. Since the radius of the spherical objects isn't mentioned anywhere, I will assume that the distance from the center of each spherical object is what's being given. The gravitational force between two masses is given as F = (G M1 M2)/r^2 where F = Force G = gravitational constant M1 = Mass 1 M2 = Mass 2 r = distance between center of masses for the two masses. So with a r value of 100 km, we have a force of 2000 Newtons. If we change the distance to 150 km, that increases the distance by a factor of 1.5 and since the force varies with the inverse square, we get the original force divided by 2.25. And 2000 / 2.25 = 888.88888.... when rounded to 3 digits gives us 889. Looking at what looks like an answer of 890 in the question is explainable as someone rounding incorrectly to 2 significant digits. If the distance is changed to 50 km from the original 100 km, then you have half the distance (50/100 = 0.5) and the squaring will give you a new divisor of 0.25, and 2000 / 0.25 = 8000. So the force increases to 8000 Newtons.</span>
8 0
3 years ago
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