All categories

3 years ago

Is it possible to add sound to a system to make it quieter?

Physics

2 answers:

algol [13]3 years ago

5 0

Sure, but you have to be really fast.

First, you use a microphone to pick up the sound that's already there. Then you generate a new wave that exactly copies the existing sound BUT it's a half wavelength (180 degrees) AFTER the original sound.

We know that if you have two waves with equal amplitudes, and they overlap, and the crest of one wave is on top of the trough of the other one, they cancel out and the result is NO WAVE. So we overlap the new wave with the existing sound, and if we got the amplitude of the new one right, it can cancel out the original sound.

That's exactly what's going on in "noise canceling" headphones.

zepelin [54]3 years ago

4 0

Yes it is possible to add sound to a system to make it quieter

You might be interested in

When all else remains the same, what effect would decreasing the focal have known a convex lens

harkovskaia [24]

Answer:

when all else remains the same, what effect would decreasing the focal have known a convex lens

Explanation:

It would cause the lens to produce only real images

( Hope This Will Help U Out!!)

4 0

3 years ago

A 62-kg person jumps from a window to a fire net 20.0 m directly below, which stretches the net 1.4 m. Assume that the net behav

gayaneshka [121]

Answer:

a) x = 0.098

b) x = 2.72 m

Explanation:

(a) To find the stretch of the fire net when the same person is lying in it, you can assume that the net is like a spring with constant spring k. It is necessary to find k.

When the person is falling down he acquires a kinetic energy K, this energy is equal to the elastic potential energy of the net when it is max stretched.

Then, you have:

$K=U\\\\\frac{1}{2}mv^2=\frac{1}{2}kx^2$ (1)

m: mass of the person = 62kg

k: spring constant = ?

v: velocity of the person just when he touches the fire net = ?

x: elongation of the fire net = 1.4 m

Before the calculation of the spring constant, you calculate the final velocity of the person by using the following formula:

$v^2=v_o^2+2gy$

vo: initial velocity = 0 m/s

g: gravitational acceleration = 9.8 m/s^2

y: height from the person jumps = 20.0m

$v=\sqrt{2gy}=\sqrt{2(9.8m/s^2)(20.0m)}=14\frac{m}{s}$

With this value you can find the spring constant k from the equation (1):

$mv^2=kx^2\\\\k=\frac{mv^2}{x^2}=\frac{(62kg)(14m/s)^2}{(1.4m)^2}=6200\frac{N}{m}$

When the person is lying on the fire net the weight of the person is equal to the elastic force of the fire net:

$W=F_e\\\\mg=kx$

you solve the last expression for x:

$x=\frac{mg}{k}=\frac{(62kg)(9.8m/s^2)}{6200N/m}=0.098m$

When the person is lying on the fire net the elongation of the fire net is 0.098m

b) To find how much would the net stretch, If the person jumps from 38 m, you first calculate the final velocity of the person again:

$v=\sqrt{2gy}=\sqrt{2(9.8m/s^2)(38m)}=27.29\frac{m}{s}$

Next, you calculate x from the equation (1):

$x=\sqrt{\frac{mv^2}{k}}=\sqrt{\frac{(62kg)(27.29m/s)^2}{6200N/m}}\\\\x=2.72m$

The net fire is stretched 2.72 m

5 0

3 years ago

What sound frequency could a human detect

finlep [7]

Answer:

People can hear sounds at frequencies from about 20 Hz to 20,000 Hz,

6 0

3 years ago

Read 2 more answers

0.8<br> How do convert this into a fraction

Umnica [9.8K]

Answer:

8/10 or 4/5

Explanation:

0.8 out of 1.0

4 0

4 years ago

A tennis ball is released from a height of 2.0 m above the floor, and then bounces three times. With each bounce, dissipative fo

Leni [432]

Answer:

12 cm

Explanation:

From what I got with my answer (8.192 cm) I went ahead and rounded it to the closest answer which is 12 cm. Hopefully im correct but if not, I apologize in advance.

3 0

4 years ago

Read 2 more answers