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ExtremeBDS [4]
3 years ago
8

The number of neutrons in the nucleus of an atom can be determined by

Chemistry
1 answer:
Tcecarenko [31]3 years ago
5 0
Since atomic mass is protons + neutrons, if you subtract atomic mass - protons, you get neutrons.
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A gold block with a mass of 325 g was heated from 22°C to 87°C. How much heat
KonstantinChe [14]

Answer:

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Explanation:

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8 0
3 years ago
What are the states of matter for the following equation?
White raven [17]

Answer:

Explanation:

On the reactant side, XeO3 is a strong oxidizing agent. It can be a solid or gas. Most likely it is in a solid state.

H+ and Br- combine to form HBr which is a weak acid. So H+ and Br- are in an aqueous state.

On the product side, both Br2 and Xe are not very soluble in water. They will be in gaseous state and H2O is water i.e. liquid state.

7 0
2 years ago
‼️SHOW ALL STEPS‼️ If 14.4 grams of iron reacts with hydrochloric acid, how many grams of hydrogen gas will be produced?
Alex Ar [27]

Answer: 0.771 g of H_2 will be produced

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} Fe=\frac{14.4g}{56g/mol}=0.257moles

The balanced chemical reaction is:

2Fe(s)+6HCl(aq)\rightarrow 2FeCl_3(aq)+3H_2(g)  

According to stoichiometry :

2 moles of Fe produce = 3 moles of H_2

Thus 0.257 moles of Fe will produce=\frac{3}{2}\times 0.257=0.385moles  of H_2  

Mass of H_2=moles\times {\text {Molar mass}}=0.385moles\times 2g/mol=0.771g

Thus 0.771 g of H_2 will be produced

3 0
3 years ago
Which group on the periodic table contains only metals?
Snezhnost [94]

Answer: GROUP  2 is the only group to include only metals. Group one includes the most metalic metals but hydrogen is usually put into group one and obviously hydrogen is not a metal. Group 2 includes Br, Mg, Ca, Sr, Ba,Ra.

Explanation:

5 0
3 years ago
Given the standard entropy values in the table, what is the value of º for the following reaction?
Mandarinka [93]
Hello.

The answer is <span>+313.766 J/mol·K
</span>
 Use the coefficients of the reaction and sum the product entropies less the reactant entropies:

4*188.8 + 2*213.7 - 3*205.1 - 2* 126.8 = 313.7 J/mol*K

Have a nice day
8 0
4 years ago
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