The formula relating acceleration and angular velocity is:
a = ω^2 r
where a is acceleration, ω is angular velocity and r is
radius
But the angular velocity ω is constant all throughout the
disk therefore:
a1 / r1 = a2 / r2
So at points:
<span>r1 = 0.0130 m ->
a1 = 393 m/s^2</span>
<span>r2 = 0.0884 m ->
a2 = ?</span>
393 / 0.0130 = a2 / 0.0884
<span>a2 = 2,672.4 m/s^2</span>
Answer:
He took a picture (or "shot") of the buffaloes. How cute :)
Answer:
speed for last lap is 247.89 km/h
Explanation:
given data
velocity v1 = 203 km/h
velocity v2 = 199 km/h
no of lap n = 10
to find out
average speed for last lap
solution
we consider here distance d for 1 lap
so in first 9 lap time taken is
t1 = distance / velocity v2
t1 = 9d / 199 ...............1
and
for 10 lap time is
t2 = 10d / 203 .............2
so from 1 and 2 equation time for last lap
last lap time t3 = t2 - t1
t3 = 10d / 203 - 9d / 199
t3 = 0.004034 d
so speed for last lap is
speed = distance / time
speed = d / 0.004034 d
speed = 247.89 km/h
so speed for last lap is 247.89 km/h