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UNO [17]
4 years ago
10

Battery of 12 V supplies charge of 1000 C to a device work battery

Physics
1 answer:
Y_Kistochka [10]4 years ago
5 0

Answer:

W = 12 kJ

Explanation:

We have,

Voltage of a battery is 12 V

Charge supplied by the battery is 1000 C

It is assumed to find the work is done by the battery in moving the charge. The work done is given in terms of voltage as :

W=qV\\\\W=1000\times 12\\\\W=12000\ J

or

W = 12 kJ

So, the work of 12 kJ is done by battery in moving charges.

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Defination coulomb's law.
-BARSIC- [3]

Answer:

a law stating that like charges repel and opposite charges attract, with a force proportional to the product of the charges and inversely proportional to the square of the distance between them.

6 0
3 years ago
Hillary is dropping objects that are the same volume. She wants to investigate how an object’s mass affects the average speed at
Artemon [7]

Answer:

letter C. The mass of the object.

Explanation:

i hope it helps.

3 0
3 years ago
A small airplane is sitting at rest on the ground. Its center of gravity is 2.58 m behind the nose of the airplane, the front wh
otez555 [7]

Answer:

The percentage of the weight supported by the front wheel is  A= 19.82 %

Explanation:

From the question we are told that

   The center of gravity of the plane to its nose  is  z = 2.58 m

    The distance of the front wheel of the plane to  its nose is l = 0.800\ m

     The distance of the main wheel of the plane to its nose is e =  3.02 \ m

At equilibrium  the Torque about the nose of the airplane is mathematically represented as

          mg (z- l) -  G_B *(e - l) = 0

Where m is the mass of the airplane

          G_B is the weight of the airplane supported by the main wheel  

       So  

             G_B =\frac{mg (z-l)}{(e - l)}

Substituting values

            G_B =\frac{mg (2.58 -0.8 )}{(3.02  - 0.80)}

           G_B = 0.8018 mg

Now the weight supported at the frontal wheel is mathematically evaluated as

           G_F = mg - G_B

Substituting values      

       G_F = mg - 0.8018mg    

      G_F = (1 - 0.8018) mg      

     G_F = 0.1982 mg    

Now the weight of the airplane is  =  mg

Thus percentage of this weight supported by the front wheel is  A = 0. 1982 *100 = 19.82 %

7 0
4 years ago
A loudspeaker in a parked car is producing sound whose frequency is 20950 Hz. A healthy young person with normal hearing is stan
rusak2 [61]

Answer:

359 m/s

Explanation:

Highest frequency a person can hear is 20,000Hz.

f = c × λ

Frequency = Wave speed × Wavelength

Wavelength = 20,000 ÷ 343 = 58.31m

Wavespeed = Frequency ÷ Wavelength

c = 20,950 ÷ 58.31 = 359.3 m/s

= 359 m/s (3 s.f.)

3 0
3 years ago
"The two equations below express conservation of energy and conservation of mass for water flowing from a circular hole of radiu
Leno4ka [110]

Answer:

The two equations below express conservation of energy and conservation of mass for water flowing from a circular hole of radius 3 centimeters at the bottom of a cylindrical tank of radius 10 centimeters. In these equations, delta m is the mass that leaves the tank in time delta t, v is the velocity of the water flowing through the hole, and h is the height of the water in the tank at time t. g is the acceleration of gravity, which you should approximate as 1000 cm/s2.

shdh

5 0
3 years ago
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